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Papessa [141]
3 years ago
13

8 = 1/13v solve this and pretty please show some simple steps

Mathematics
1 answer:
prohojiy [21]3 years ago
6 0
8=1/13 v
first step: multiply both sides by 13 to get v alone
1/13 x 13=1
8x13=104
the answer is v=104
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Supposed the population of deer in a region was 3,500 in the year 2000.since then population has grown by 3.5% annually. What wi
sergejj [24]
Y = a (b^x)

1) x = 0, y = 3500

=> 3500 = a (b^0)

=> 3500 = a (1)

=> a = 3500

2) growth percent = 3.5% => growth rate = 1.035 = b

=> y = 3500 (1.035)^ x

3) year 2020 => x = 2020 - 2000 = 20

4) y = 3500 (1.035)^ 20 = 6964

Answer: 6964.

3 0
3 years ago
The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
4 years ago
Solve 3x2−3x=0 by factoring.
o-na [289]

Answer:

3x(x-1) = 0

x= 1

Step-by-step explanation:

is 3x2 supposed to mean 3x^2 i dont know

5 0
3 years ago
a box has a length of 15 centimetres , a width of 22 centimetres, and a height of 9 centimetres.what is the surface area of the
zzz [600]

Answer:

1326 cm²

Step-by-step explanation:

1) Identify the equation of the surface area of a rectangular prism

       A = 2(wl + wh + hl)

2) Input the corresponding values l=15 cm; w=22 cm; and h=9 cm into the equation, and solve for the area

       A=2(wl+wh+hl)\\A=2((22)(15)+(22)(9)+(9)(15))\\A=2(330+198+135)\\A=2(663)\\A=1326 cm^{2}

3) ∴ A=1326cm^2

5 0
2 years ago
Find the area of the shape shown<br> below.
Allisa [31]

Answer:

The area of the figure is 28 units².

Step-by-step explanation:

Find the area of the full rectangle, ignoring the triangle.

a = lw \\ a = 4 \times 8 = 32

Then, find the area of the triangle:

a =  \frac{bh}{2}  \\ a =  \frac{2 \times 4}{2}  \\ a = 4

Finally, subtract:

32 - 4 = 28

7 0
3 years ago
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