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3 years ago

I need help in these 2 problems it is a picture

Mathematics

1 answer:

Sholpan [36]3 years ago

8 0

5) adding 2 each time

i can't help with number 6 sorry i hope number 5 helps

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Miss holman gave 90-cent trip to a waitress for serving for a meal coasting 6.00. What percent of the bill was there tip

Darina [25.2K]

Here you go :)
0.90/6.00 *100=15%

4 0

3 years ago

Juan unloads 29 bags of pine mulch from each of his fathers 2 trucks. Together, the truck holds 2,262 pounds of pine mulch. What

Tamiku [17]

I think the weight is 78 pounds for each bag. I could be wrong.. I'm not sure. I did 2,262 divided by 29.

7 0

4 years ago

Solve for x 3(x+2)+4(x-5)=10

Natasha_Volkova [10]

Answer:

x=24/7

Step-by-step explanation:

3(x+2)+4(x-5)=10

3x+6+4(x-5)=10

3x+6+4x-20=10

7x+6-20=10

7x-14=20

7x=24

x=24/7

8 0

3 years ago

There are 12 students in the pep squad.Three students are wearing white shirts.Six students are wearing blue shirts. What fracti

Viktor [21]

Answer:

$\frac{3}{4}$

Step-by-step explanation:

Total number of the students in the pep squad = 12 students

The number of the students wearing white shirts = 3 students

The number of the students wearing blue shirts = 6 students

Either white or blue shirts indicate that the students wearing white shirt or blue shirt.

Thus, number of students wearing either white or a blue shirt = 3 + 6 students = 9 students

So,

The fraction is:- $\frac{9}{12}=\frac{3}{4}$

5 0

3 years ago

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the

liberstina [14]

Answer:

188 children and 145 adults were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be $x.$

And the the number of adults admitted be $y.$

So, the total people enter the park:

$x+y=333\\\\x=333-y\ \ \ ...(1)$

Thus, the total amount collected of the admission fee:

$1.50(x)+4(y)=862\\\\$

Substituting the value of $x$ from equation (1):

$1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.$

Thus, the number of adults = 145.

Now, to get the number of children by substituting the value of $y$ in equation (1) we get:

$x=333-y\\\\x=333-145\\\\x=188.$

Hence, the number of children = 188.

Therefore, 188 children and 145 adults were admitted in the park.

4 0

4 years ago