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Greeley [361]
4 years ago
14

What is the slope for 2x-1=-3y

Mathematics
1 answer:
dexar [7]4 years ago
5 0

Answer:

The slope is -2/3

Step-by-step explanation:

It is recommended to solve for 'y' variable the equation given, this means, leave the 'y' variable alone in one side of the equation. Doing that, leaves us the following:

y=\frac{-2}{3}x +\frac{1}{3}

This is the general equation of a line: y=mx+b where 'm' is the slope (by comparison), thus We have the desired result

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A school is organising a competition. There are 128 students from the Maths specialist class and 80 students from the English sp
Elden [556K]

Answer:

5 english students in each team

Step-by-step explanation:

So there are multiple ways to do this, you could do trial and error or you could factor out common numbers between the two.

Through trial and error, the lowest possible number of groups that could be divided between the number of students whilst still being able to maintain a whole # was 16 groups

  • 128 math students ÷16 groups = 8 math students/group
  • 80 english students ÷ 16 groups = 5 english students/group

The other way to solve this is to factor out common numbers between the two:

3 0
2 years ago
Which angle corresponds to &lt;7?<br> A. &lt;1<br> B. &lt;3<br> C. &lt;4<br> D. &lt;6
DiKsa [7]
B.

Use the photo for future references.

4 0
3 years ago
1879 meters to kilometers
lesantik [10]
It would be 1.879 kilometers
6 0
3 years ago
Solve the differential equation: dy/dx = 4y2x1/3
labwork [276]
The first thing you should do is use the method of variable separation. Then, integrate both sides to find the solution.
 In this case the answer is
  <span>D. - 1/y = 3x4/3 + C</span> 
 I attach the solution

4 0
3 years ago
Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .
Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of F around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

           F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle

Therefore,

                  P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y

Let's calculate the needed partial derivatives.

                              P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0

Thus,

                                    Q_x -P_y = 0 -2 = - 2

Now, by the Green's theorem, we have

\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x  \Big|_{-3}^{4} = -42

4 0
3 years ago
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