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Greeley [361]
4 years ago
14

What is the slope for 2x-1=-3y

Mathematics
1 answer:
dexar [7]4 years ago
5 0

Answer:

The slope is -2/3

Step-by-step explanation:

It is recommended to solve for 'y' variable the equation given, this means, leave the 'y' variable alone in one side of the equation. Doing that, leaves us the following:

y=\frac{-2}{3}x +\frac{1}{3}

This is the general equation of a line: y=mx+b where 'm' is the slope (by comparison), thus We have the desired result

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Guys, please help me with this problem.
SashulF [63]
<h2>Answer:</h2>

The number is -2.

<h2>Step-by-step explanation:</h2><h3>Written out, our equation looks like this:</h3><h3>(-5·x)+2=12</h3>

We'll start of by taking our final result of 12 and subtracting 2, as the beginning of the statement says "two more."

<h3>12 minus 2 gives us 10.</h3>

Now, since the statement says "the product of -5," we will take this 10 and divide by -5.

<h3>10 divided by -5 gives us -2.</h3>

This means that our number, x equals -2. Of course, we must input this solution to double check our work.

<h3>(-5·<u>-2</u>)+2=12</h3><h3>10+2=12</h3><h3>12=12</h3>

<h2>Our final answer is x=-2!</h2>
3 0
3 years ago
Read 2 more answers
rectangle DOIT has vertices at D(-20,3) O(20,3) I(20,-6) T(-20,-6) what is the area of rectangle DOIT
AnnZ [28]

Answer:

360 sq. units

Step-by-step explanation:

area of DOIT = (20+20) × (3+6)

= 40×9 = 360 sq. units

7 0
3 years ago
Jay had 6 times as much money as Kay. Then Jay gave Kay $33. Jay now has twice as much money as Kay. How much did they each star
timofeeve [1]

Answer:

Jay started with $148.5 and Kay with $24.75.

Step-by-step explanation:

With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:

J=6K, where

J is the money Jay had

K is the money Kay had

Also, you know that  Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:

J-33=2(K+33)

Now, you can replace J=6K in this equation and solve for K:

6K-33=2K+66

6K-2K=66+33

4K=66

K=24.75

Then, you can replace the value of K in J=6K:

J=6*24.75

J=148.5

According to this, the answer is that Jay started with $148.5 and Kay with $24.75.

7 0
3 years ago
Help me please :).........
VikaD [51]
C I believe it not so sure
5 0
4 years ago
90 points please help!!!!!!!!
just olya [345]
To model this situation, we are going to use the exponential function: f(t)=P(1+ \frac{r}{n} )^{nt}
where
P is the initial number of cars
r is the growing rate in decimal form 
n is number of tames the growing rate is increasing per year
t is the time in years

To convert the growing rate to decimal form, we are going to divide the rate by 100%
r= \frac{12}{100}
r=0.12
Since the growing rate is increasing quarterly, n=4. We also know that the initial number of cars is 920, so P=920. Lets replace all those values in our function:
f(t)=920(1+ \frac{0.12}{4} )^{4t}
f(t)=920(1+0.03)^{4t}
f(t)=900(1.03)^{4t}

We can conclude that:
Rate ---------> The quarterly rate of growth is 0.03 or 3%
Exponent --------> The compound periods multiplied by the number of years                                 is 4t
Coefficient--------> The initial number of cars serviced is 920
Base------> The growth factor is represented by 1.03
3 0
3 years ago
Read 2 more answers
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