2^2x=5^x−1
Take the log pf both sides:
ln(2^2x) = ln(5^x-1)
Expand the logs by pulling the exponents out:
2xln(2) = (x-1)ln(5)
Simpligy the right side:
2xln(2) = ln(5)x - ln(5)
Now solve for x:
Subtract ln(5)x from both sides:
2xln(2) - ln(5)x = -ln(5)
Factor x out of 2xln(2)-ln(5)x
x(2ln(2) - ln(5)) = -ln(5)
Divide both sides by (2ln(2) - ln(5))
X = - ln(5) / (2ln(2) - ln(5))
Answer:
the answer is 2
Step-by-step explanation:
add -4x and -6x and the answer is -10x bc they are both negative x. then divide both -10x and -20 by -10 so that it is x by itself on one side and 2 on the other so its 2=x :)
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Sorry if this is wrong!!
