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2 years ago

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A solid metal rectangular pyramid has a base that measures 16 cm by 25 cm The Solid is melted and recast into a solid cavare pyr

amid of the same height. Find the length of the side of the base of the square pyramid.

1 answer:

Ymorist [56]2 years ago

5 0

12 yesyrsyrsjsnskwnbewnisenenekek

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Search results for There were 35 bunches of roses and tulips. Each brunch at 12 of the same flowers. There were seven more bunch

KIM [24]

If it is supposed to say <span>seven more bunches of tulips than roses, that would mean, if there are 35 bunches in all, and if each bunch had 12 of the same flowers.... that must mean each bunch had 12 flowers so, 12*1/2/35. 35/1/2 would be 35/0.5 that would equal... 17.5. so, 12*17.5= 210. if there was seven more added, than, 7/2= 3.5 and 12*3.5= 42. 210+42=252.

That means there are 252 tulips, i might be wrong (i probably am), i am just going by logic, lol
</span>

3 0

3 years ago

The first aspect of the argument you must evaluate is the truth of the reasons that are being used to support a conclusion. (Poi

Marina86 [1]

True because it the reasons used to support the conclusion are fake or false, then the argument is lost

6 0

3 years ago

Read 2 more answers

Simplify 12x6 y7 18 x3y5.

Ksivusya [100]

Answer:

216x^9y^12

Step-by-step explanation:

5 0

3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago

Find the length of each arc. Use the exact answer

Cerrena [4.2K]

Answer:

Option D = 16π/3 ft

Step-by-step explanation:

Arc length formula is written Mathematically as:

Arc length = 2πr × θ /360

r = 4 ft

θ = Central angle in degrees = 240°

2 × π × 4 × 240/360

8π × 240/360

8π × 20/30

16π/3 ft

So, the arc length is 16π/3 ft

3 0

3 years ago