Answer:
-10
Step-by-step explanation:
On the number line -9 appear before -10. Thw futher the number, the smaller it gets
This is a problem pertaining projectile motion wherein the parameter we're finding is the angle of inclination denoted as theta. The formula to be used is the range:
Range = v^2*sin(2*theta)*(1/g)
100 = (60^2) * sin(2*theta) * (1/32.2)
theta=31.7°
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Answer:
52
Step-by-step explanation:
Given the the equation h(t) =-
where t is the time in second
So to find the ball's maximum height we can apply the vertex formula:
t=
to find the "x" value of the vertex, then plug that value into the original equation as a substitute for "x".
Standard quadratic form is:
=> a=15, b=30 in our given equation
<=> t =
When t =-1 we have h(t) =
= 52
So the ball's maximum height is: 52
Hope it will find you well.
14^a is your answer hope i helped you
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