according to the question
3x-1=0
3x=1
x=⅓
so
f(x)=18x³+x-1
f(⅓)=18.(⅓)³+⅓-1
f(⅓)=18.⅓.⅓.⅓+⅓-1
f(⅓)=6.⅑+⅓-1
f(⅓)=⅔+½-1
f(⅓)=0
<h3>therefore</h3><h3> the remainder is 0</h3>
Answer:
im gonna say 4 if im wrong its my fault
Whats the rest of the problem?
5678(1+(0.045×6))
5678=P as it is the principal amount
The area is 126in^2
Hope this helps