Answer:
At least 75% of these commuting times are between 30 and 110 minutes
Step-by-step explanation:
Chebyshev Theorem
The Chebyshev Theorem can also be applied to non-normal distribution. It states that:
At least 75% of the measures are within 2 standard deviations of the mean.
At least 89% of the measures are within 3 standard deviations of the mean.
An in general terms, the percentage of measures within k standard deviations of the mean is given by 
.
In this question:
Mean of 70 minutes, standard deviation of 20 minutes.
Since nothing is known about the distribution, we use Chebyshev's Theorem.
What percentage of these commuting times are between 30 and 110 minutes
30 = 70 - 2*20
110 = 70 + 2*20
THis means that 30 and 110 minutes is within 2 standard deviations of the mean, which means that at least 75% of these commuting times are between 30 and 110 minutes
Answer:
if 1/6 of a roll of paper covers 1/4 of a wall, this means that we will need 4/6 of a roll to cover a whole wall, now the question is asking how many rolls will we need to cover 4 walls, we already know that it takes 4/6 to fill one wall so if we add 4/6+4/6+4/6+4/6 we will get 16/6 or 2 4/6
we will need 16/6 or 2 4/6 of rolls of paper to cover 4 walls
Answer:
1.345*10^7
Step-by-step explanation:
Here we need to rewrite 13,450,000 in scientific notation, which looks like x.xx*10^n.
To move the decimal point in 13,450,000 to its proper place between the 3 and the 4, a move of 7 digits, we need to multiply 1.345 by 10^7.
13,450,000 in scientific notation is 1.345*10^7.
Answer:
•A c-chart is the appropriate control chart
• c' = 8.5
• Control limits, CL = 8.5
Lower control limits, LCL = 0
Upper control limits, UCL = 17.25
Step-by-step explanation:
A c chart is a quality control chart used for the number of flaws per unit.
Given:
Past inspection data:
Number of units= 100
Total flaws = 850
We now have:
c' = 850/100
= 8.5
Where CL = c' = 8.5
For control limits, we have:
CL = c'
UCL = c' + 3√c'
LCL = c' - 3√c'
The CL stands for the normal control limit, while the UCL and LCL are the upper and lower control limits respectively
Calculating the various control limits we have:
CL = c'
CL = 8.5
UCL = 8.5 + 3√8.5
= 17.25
LCL = 8.5 - 3√8.5
= -0.25
A negative LCL tend to be 0. Therefore,
LCL = 0
