is less steep than the parent quadratic equation, while 
is steeper than the parent quadratic equation
<h3>How to determine the equations</h3>
The parent equation of a quadratic equation is represented as:
For a function to be steeper or less steep than the parent function must be stretched or compressed by a factor k
So, we have:
If k is greater than 1, then the function would be steeper; else, the function would be less steep.
Assume k = 2, we have:
Assume k = 1/2, we have:
Hence, is less steep than the parent quadratic equation, while is steeper than the parent quadratic equation
Read more about quadratic equations at:
brainly.com/question/11631534
D = √( (x2 - x1)^2 + (y2 - y1)^2 )
D = √( (15-3)^2 + (16 - 7)^2 )
D = √ ( 12^2 + 9^2 )
D = √ (144 + 81)
D = √225
D = 15
If it is 1st degree (highest exponent is 1) then it is linear
3x^1=5y^1
yep, it's linear
X = 0 y = 15(0) - 4 = -4
x = 1 y = 15(1) - 4 = 11
x = 2 y = 15(2) - 4 = 26
x = 3 y = 15(3) - 4 = 41
x = 4 y = 15(4) - 4 = 56
x = 5 y = 15(5) - 4 = 71
range = largest - smallest
71 - -4 = 75
so the range is 75
Answer: -2
Step-by-step explanation: add the -8 to both sides to get X by itself
-10 + 8 = -2
