That would be (9x2 - 25 = (3x-5) (3x+5)
Answer:
ans=13.59%
Step-by-step explanation:
The 68-95-99.7 rule states that, when X is an observation from a random bell-shaped (normally distributed) value with mean
and standard deviation
, we have these following probabilities
![Pr(\mu - \sigma \leq X \leq \mu + \sigma) = 0.6827](https://tex.z-dn.net/?f=Pr%28%5Cmu%20-%20%5Csigma%20%5Cleq%20X%20%5Cleq%20%5Cmu%20%2B%20%5Csigma%29%20%3D%200.6827%20)
![Pr(\mu - 2\sigma \leq X \leq \mu + 2\sigma) = 0.9545](https://tex.z-dn.net/?f=Pr%28%5Cmu%20-%202%5Csigma%20%5Cleq%20X%20%5Cleq%20%5Cmu%20%2B%202%5Csigma%29%20%3D%200.9545)
![Pr(\mu - 3\sigma \leq X \leq \mu + 3\sigma) = 0.9973](https://tex.z-dn.net/?f=Pr%28%5Cmu%20-%203%5Csigma%20%5Cleq%20X%20%5Cleq%20%5Cmu%20%2B%203%5Csigma%29%20%3D%200.9973)
In our problem, we have that:
The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 53 months and a standard deviation of 11 months
So ![\mu = 53, \sigma = 11](https://tex.z-dn.net/?f=%5Cmu%20%3D%2053%2C%20%5Csigma%20%3D%2011)
So:
![Pr(53-11 \leq X \leq 53+11) = 0.6827](https://tex.z-dn.net/?f=Pr%2853-11%20%5Cleq%20X%20%5Cleq%2053%2B11%29%20%3D%200.6827)
![Pr(53 - 22 \leq X \leq 53 + 22) = 0.9545](https://tex.z-dn.net/?f=Pr%2853%20-%2022%20%5Cleq%20X%20%5Cleq%2053%20%2B%2022%29%20%3D%200.9545)
![Pr(53 - 33 \leq X \leq 53 + 33) = 0.9973](https://tex.z-dn.net/?f=Pr%2853%20-%2033%20%5Cleq%20X%20%5Cleq%2053%20%2B%2033%29%20%3D%200.9973)
-----------
![Pr(42 \leq X \leq 64) = 0.6827](https://tex.z-dn.net/?f=Pr%2842%20%5Cleq%20X%20%5Cleq%2064%29%20%3D%200.6827)
![Pr(31 \leq X \leq 75) = 0.9545](https://tex.z-dn.net/?f=Pr%2831%20%5Cleq%20X%20%5Cleq%2075%29%20%3D%200.9545)
![Pr(20 \leq X \leq 86) = 0.9973](https://tex.z-dn.net/?f=Pr%2820%20%5Cleq%20X%20%5Cleq%2086%29%20%3D%200.9973)
-----
What is the approximate percentage of cars that remain in service between 64 and 75 months?
Between 64 and 75 minutes is between one and two standard deviations above the mean.
We have
subtracted by
is the percentage of cars that remain in service between one and two standard deviation, both above and below the mean.
To find just the percentage above the mean, we divide this value by 2
So:
![P = {0.9545 - 0.6827}{2} = 0.1359](https://tex.z-dn.net/?f=P%20%3D%20%7B0.9545%20-%200.6827%7D%7B2%7D%20%3D%200.1359)
The approximate percentage of cars that remain in service between 64 and 75 months is 13.59%.
Hello, the answer is x=-1/2
Here are the steps....
<span><span><span><span><span>−<span>7x</span></span>+12</span>+</span>−<span>2x</span></span>=<span>23+<span>13x</span></span></span><span><span><span>(<span><span>−<span>7x</span></span>+<span>−<span>2x</span></span></span>)</span>+<span>(12)</span></span>=<span><span>13x</span>+23</span></span>(Combine Like Terms)<span><span><span>−<span>9x</span></span>+12</span>=<span><span>13x</span>+23</span></span><span><span><span>−<span>9x</span></span>+12</span>=<span><span>13x</span>+<span>23
</span></span></span><span><span><span><span>−<span>9x</span></span>+12</span>−<span>13x</span></span>=<span><span><span>13x</span>+23</span>−<span>13x</span></span></span><span><span><span>−<span>22x</span></span>+12</span>=<span>23
</span></span><span><span><span><span>−<span>22x</span></span>+12</span>−12</span>=<span>23−12</span></span><span><span>−<span>22x</span></span>=<span>11
</span></span><span><span>−<span>22x</span></span><span>−22</span></span>=<span><span><span>11<span>−22</span></span></span></span><span>x=<span><span><span>−1</span>2</span></span></span><span>
</span>Hope this helps you!!
AC¯¯¯¯¯≅PQ¯¯¯¯¯ is true.
Congruent<span>. Exactly equal in size and shape. </span>Congruent<span> sides or
segments have the exact same length. </span>Congruent<span> angles have the exact same measure. For any set of </span>congruent<span> geometric
figures, corresponding sides, angles, faces, etc. are congruent.</span>
I am hoping that this answer has
satisfied your query and it will be able to help you in your endeavor, and if
you would like, feel free to ask another question.
Answer:
10
Step-by-step explanation:
15 divided by 3 is 5, and 5 times 2 is 10 :)