The answer should be A.
When we see the equation y=a^x we can relate to all the exponential functions, however, when the problem asked what points does all equations in that form pass through. I was instantly reminded by two facts.
One is that any number to the first is equal to itself. In other words, a^1=a
Another is that any number to the zero is equal to 1. a^x=1
if that is true, 1 will always be the x value since y=a^x and 0 will always be the x value because that is how y can be equal to one.
therefore, the answer is A: (0,1)
Answer:
Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9) is
Linear Relationship i.e 
Step-by-step explanation:
Given:
Let,
point A( x₁ , y₁) ≡ ( -7, 5 )
point B( x₂ , y₂) ≡ (-5, 9)
To Find:
Equation of Line AB =?
Solution:
Equation of a line passing through Two points A( x₁ , y₁) and B( x₂ , y₂)is given by the formula
Substituting the given values in a above equation we get
Therefore the equation of the line through ( -7 , 5 ) and ( -5 , 9 ) is
Linear Relationship i.e
I think it’s 1/5 if that’s an answer option
log was used calculate big numbers before calculators
log is a re-arranged way to show a number with an exponent
example
log₂ 16 = 4 means 2^4 = 16
logx(Z) = y means x^y=Z
log(x-6)/log(2) + log(x)/log(2) = 4
(log(x-6)+ log(x))/log(2) = 4
(log(x-6)+ log(x)) = 4log(2)
(log(x-6)x) = log(16)
x=8
Answer:
23x-1
Step-by-step explanation:
