Answer:
<h2>90 min or 1hr 30 mins</h2>
Step-by-step explanation:
Even though the options to choose from are not given in this question we can try and lay our hand on the most likely equation for the number of minutes Jack reads his book.
firstly on a daily Jack reads a total of = 8+10 = 18 mins
He attends school from Mon- fri = 5 days
Now on a weekly basis jack reads = 5*18
in other words, the equation is simply the number of days times the time spent to read his book per day
hence this is = 90 min or 1hr 30 mins
Answer:
65
Step-by-step explanation:
First, let's consider the case where you have 1 apple in the basket. The possible number of baskets you can have with 1 apple is 11: the case where you have no oranges besides the apples, the case where you have 1 orange, the case where you have 2 orange, etc.
This line of reasoning can be followed by each possible amount of apples you can have: 0, 1, 2, 3, 4 and 5.
Keep in mind that in the case where you have no apples, you must exclude the case where you also have no oranges, because the problem tells you that the basket must have at least 1 fruit.
So, the answer would be:
x = 6*11 -1 = 65 possible baskets
Answer:
move the decimal point in 4.082 4 places to the left
Step-by-step explanation:
i hope this helps :)
<span>When rates are expressed as a quantity of 1, such as 2 feet per second or 5 miles per hour, they are called unit rates. If you have a multiple-unit rate such as 120 students for every 3 buses, and want to find the single-unit rate, write a ratio equal to the multiple-unit rate with 1 as the second term.</span>
Answer:
2 is the average rate of change of the function
from
to
.
Step-by-step explanation:
I assume you meant
based off the points.
We are given that
and
are points on this curve.
We are asked to find the average rate of change (the slope) from
to
.
We have the two points needed to find the slope.
We just need to line them up and subtract vertically then put 2nd difference on top of 1st difference.


--------------------Subtracting!

So the slope is
.