I cant help you there m8 the I'm not able to see the problem I'm sorry.
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Find the duration
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Time : 9:00am to 10:15am
Duration: 1hour 15 mins or 1.25hours
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Find difference in distance travelled between the two cyclists.
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Difference in speed = 6km/h
1 hour = 6 km
1.25 hours = 7.5km
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Find the distance the cyclist traveled
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42.5 - 7.5 = 35km
35km ÷ 2 = 17.5km
The slower cyclist traveled 17.5 km in the 1.25 hours
17.5 + 7.5 = 25 km
The faster cyclist traveled 25km in the 1.25 hours
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Find the speed of the slower cyclist
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1.25 hour = 17.5 km
1 hour = 17.25 ÷ 1.25
1 hour = 14km
The cyclist was traveling at 14km/h
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Find the speed of the faster cyclist
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1.25 hour = 25km
1 hour = 25 ÷ 1.25
1hour = 20 km
The cyclist was traveling at 20km/hour
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Answer: The speed were 14km/h and 20 km/h
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Answer:
14x-19
Step-by-step explanation: Now can someone answer my question look at my page
-6n-20=-2n+4-12n
-6n-20=-14n+4
+6n +6n
-20=-8n+4
-4 -4
-24=-8n
/8 /8
n=-3
-
F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
