<span>So we want to know how much clay did Joseph add after he built the cone. So the formula for the volume of the cone is V=(1/3)*pi*r^2*h where r is the radius and h is height. We know h1=12cm and r1=6cm, r2=6cm and h2=18 cm. So to get the amount of added clay Va we simply subtract the volume of the clay of the first cone V1 from the volume of the second cone V2: Vd=V2-V1=(1/3)*pi*(r1^2)*h1 - (1/3)+pi*(r2^2)*h2. Va=678.24 cm^3-452.39 cm^3= 266.08 cm^3.</span>
1. 16
2. 10
3. ?
4?
for 3 and 4 I think you use a protractor
Answer:
Step-by-step explanation:
Answer:
v=20, w=80
Step-by-step explanation:
First, we can find v by determining that angle 5v and angle 4v and supplementary to each other. This means that their sum adds up to 180 degrees.
5v + 4v=180
9v=180
v=20
We also know 4v is equivalent to w.
4(20)=w
w=80
Answer:
s= 14
Step-by-step explanation:
The missing side is s
sin 30° = 7/s switch s and sin 30°
s = 7/sin 30°
sin 30° is 0.5
so :