Question

Do the same exercise but this time use the value returning function. Here is the skeleton of the main function. Write functions definition according to the function call. Note: Do not change the main(). Copy it as it is. Must define the function after the main(). Make sure you write the function prototype before main(). // function prototype.

Answer 1

Answer:

The function prototypes are as follows:

int findSum(int fn, int sn, int tn);

int findMin(int fn, int sn, int tn);

int findMax(int fn, int sn, int tn);

The functions are as follows:

int findSum(int fn, int sn, int tn){

   return fn+sn+tn;}

int findMin(int fn, int sn, int tn){

   int min = fn;

   if(sn<=min && sn<=tn){

       min = sn;    }

   if(tn <= min && tn <= sn){

       min = tn;    }

   return min;}

int findMax(int fn, int sn, int tn){

   int max = fn;

   if(sn>=max && sn>=tn){

       max = sn;    }

   if(tn>=max && tn>=sn){

       max = tn;    }

   return max;}

Explanation:

Given

See attachment 1 for the main function

Required

Write the following functions

• findSum
• find Min
• findMax.

The following represents the function prototypes

int findSum(int fn, int sn, int tn);

int findMin(int fn, int sn, int tn);

int findMax(int fn, int sn, int tn);

This declares the findSum function

int findSum(int fn, int sn, int tn){

This returns the sum of the three numbers

   return fn+sn+tn;}

This declares the findMin function

int findMin(int fn, int sn, int tn){

This initialzes min (i.e. minumum) to fn

   int min = fn;

This checks if sn is the minimum

   if(sn<=min && sn<=tn){

       min = sn;    }

This checks if tn is the minimum

   if(tn <= min && tn <= sn){

       min = tn;    }

This returns the minimum of the three numbers

   return min;}

This declares the findMax function

int findMax(int fn, int sn, int tn){

This initialzes max (i.e. maximum) to fn

   int max = fn;

This checks if sn is the maximum

   if(sn>=max && sn>=tn){

       max = sn;    }

This checks if tn is the maximum

   if(tn>=max && tn>=sn){

       max = tn;    }

This returns the maximum of the three numbers

   return max;}

See cpp attachment for complete program which includes the main