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bekas [8.4K]
3 years ago
8

Find the value of x for this shape

Mathematics
1 answer:
aliya0001 [1]3 years ago
4 0

Answer:

10

Step-by-step explanation:

92+100+102=294

360-294=66

5x+16=66

5x=66-16

5x=50

x=50/5

x=10

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Which of the following inequalities have the same solution set? Select all that apply (>= means greater than or equal to and
Alex_Xolod [135]
<span>7n + 4 - 5n <= 2(n+2) Let's simplify these expression first 2n + 4 <= 2(n + 2) 2(n +4) = 2n + 4 The LHS and RHS expressions are the same but the inequality says contrary Hence 2n + 4 is not less than but equal to 2(n + 2). 7+ 6a >= -4(2-a) - 2a -4(2-a) - 2a = -8 + 4a - 2a = -8 + 2a. It should be obvious that 7 +6a is greater than the RHS expression. Suppose a= 2 then we have 7 + 6(2) = 19 while -8 + 2(2) = - 8 + 4 = -4 So it follows that 7 + 6a >= -4(2-4) -2a 4x >= 8. The expression is always true so the equal to option is out.</span>
5 0
3 years ago
it will cost $285 to charter a bus for a class trip. the class treasurer says that there is $60 in the class treasury. the 20 st
dalvyx [7]
(285-60)/20
Which is $11.25 per child
4 0
4 years ago
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Pls help I will give u brainlest whoever is first and gets it right!
Viktor [21]

Answer:

the answer is D

Step-by-step explanation:

3 0
3 years ago
Mickey said that 45.7654 rounded to the nearest thousandth is 45.765 and Nicole said that it was 45.766. Who is correct and why?
Nesterboy [21]

Answer:

Mickey

Step-by-step explanation:

Mickey is correct because if you look at the number 45.7654 whenever you round to the nearest thousandth it'll be 45.765

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8 0
3 years ago
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Solve for x use the completing the square method x^2+6x=5
Mrac [35]

Answer:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

Step-by-step explanation:

x^{2}+6x-5=0

we divide the coefficient of the X by half :

in this case: 6/2 = 3 , then we do the following

The result obtained is raised to square power:  3^2=9

we sum and subtract by 9 to maintain the balance of the equation:

x^{2}+6x+9-9-5=0

we have:

(x+3)^{2}-9-5=0

(x+3)^{2} = 14

lets apply square root on both sides of the equation:

\sqrt{(x+3)^{2}}=\sqrt{14}

we know:

\sqrt{a^{2}} = abs(a)

so we have:

abs(x+3)=\sqrt{14}

from where two solutions are obtained

x_{1} + 3 =\sqrt{14} \\\\x_{2} + 3 =-\sqrt{14}

finally we have:

x_{1} =-3 +\sqrt{14} \\\\x_{2} =-3 -\sqrt{14}

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4 years ago
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