You want to find the equation for a line that passes through the point (-1,5) and has a slope of 4.
First of all, remember what the equation of a line is:
y = mx+b
Where:
m is the slope, and
b is the y-intercept
To start, you know what m is; it's just the slope, which you said was 4. So you can right away fill in the equation for a line somewhat to read:
y=4x+b.
Now, what about b, the y-intercept?
To find b, think about what your (x,y) point means:
(-1,5). When x of the line is -1, y of the line must be 5.
Answer:
6
Step-by-step explanation:
Triangle OPQ is shown below with line RS passing through points R and S:
Triangle OPQ is shown with point R lying on side OP and point S lying on side OQ Line RS is perpendicular to side OQ.
If triangle OPQ is dilated about the center of the triangle to create triangle O'P'Q', what can you conclude about segments RS and R'S'? (6 points)
Segment O'Q' is perpendicular to segment R'S'. Line RS is parallel to line R'S'. Line RS is perpendicular to line R'S'. Point P' passes through line RS.
It’s B
PEMDAS. Exponents first then divide then add
