Answer:

Using Pedmas rule:

<u>subtract: 6-6 = 0</u>

<u>simplify the following</u>

<u>the numerator and denominator cancels out</u>

Step-by-step explanation:
the equation :
Hn = 7n + 3
where :
Hn : the height of trees at year to-n
n : year to-n (n = 1,2,3,...)
so, the rate of change : increasing 7 feet per year.
check the template in the picture below.
so the graph of f(x) is simply expanded horizontally, meaning the value A*B changed to something less than 1.
![\begin{array}{|l|cc|ll} \cline{1-3} &x&y\\ \cline{2-3} f(x)=x^2&2&4\\[1em] g(x)=\frac{1}{2}x^2&2&2\\ \cline{1-3} \end{array}](https://tex.z-dn.net/?f=%5Cbegin%7Barray%7D%7B%7Cl%7Ccc%7Cll%7D%20%5Ccline%7B1-3%7D%20%26x%26y%5C%5C%20%5Ccline%7B2-3%7D%20f%28x%29%3Dx%5E2%262%264%5C%5C%5B1em%5D%20g%28x%29%3D%5Cfrac%7B1%7D%7B2%7Dx%5E2%262%262%5C%5C%20%5Ccline%7B1-3%7D%20%5Cend%7Barray%7D)
Given,
9(x+1) = 25 + x
expanding,
9x + 1 = 25 + x
bringing x to left hand side and taking 1 to right hand side with change in their respective signs,
9x - x = 25-1
=> 8x = 24
transposing 8 ,
=> x = 24/8 = 3
Hence x = 3
From F.S 1, consider this series : 8, 1, 8, 8, 64, 64*8.
Again, consider the series 2, 1/4, 1/2, 1/8, 1/16, 1/(8*16). Clearly, the difference of the 6th and the 3rd term is different for them. Insufficient.
<span>From F.S 2, let the series be </span><span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span><span>a,b,ab,a<span>b2</span>,<span>a2</span><span>b3</span>,<span>a3</span><span>b5</span></span></span><span>. Now we know that </span><span><span>a<span>b2</span>=1</span><span>a<span>b2</span>=1</span></span>. The required difference =<span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span><span><span>a3</span><span>b5</span>−ab=ab(<span>a2</span><span>b4</span>−1)=ab[(a<span>b2</span><span>)2</span>−1]</span></span><span>= 0.Sufficient.</span>