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DENIUS [597]
3 years ago
9

What’s 1/2 + 1/3? Y’all please help me . And when or if you can give me the answer can you do step-by-step on how you did that s

o I can do it myself next time?
Mathematics
2 answers:
antiseptic1488 [7]3 years ago
7 0
Hi! 1/2 + 1/3 is 5/6.

2 + 3 = 5
2 X 3 = 6

= 5/6

I hope this helped if I can help in anyway I would be happy to help you. Goodluck :)
Katen [24]3 years ago
4 0

\longrightarrow{\green{\frac{5}{6}}} 

\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}

\frac{1}{2}  +  \frac{1}{3}

Since the denominators are unequal, we find the L.C.M (lowest common multiple) for both denominators.

The L. C. M for 2 and 3 is 6.

Now, multiply the L.C.M. with both numerator & denominator.

= \frac{1 \times 3}{2 \times 3}  +  \frac{1 \times 2}{3 \times 2}

=  \frac{3}{6}  +  \frac{2}{6}

Now that the denominators are equal, we can add them.

=  \frac{3 + 2}{6}  \\  \\  =  \frac{5}{6}

\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{♡}}}}}

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\mathcal \pink{Answer}

\mathcal \green{3x = 30}

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A(7x + 3) = b + 14x what The value of A
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Find mean, median, mode for the following. The following table of grouped data represents the weight (in pounds) of 100 Computer
ExtremeBDS [4]

Answer:

<em>A.(for weight in pounds)</em>

3, 4, 5, 6, 7

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Mode: There are no mode in the following data set.

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5 0
3 years ago
assume x and y are both differentiable functions of t. find dx/dt given x=-1 and dy/dt=8 for the relation: 4x^2+3y^3=28
melomori [17]

Given:

x and y are both differentiable functions of t.

4x^2+3y^3=28

x=-1\text{ and }\dfrac{dy}{dt}=8

To find:

The value of \dfrac{dx}{dt}.

Solution:

We have,

4x^2+3y^3=28       ...(i)

At x=-1,

4(-1)^2+3y^3=28

4+3y^3=28

3y^3=28-4

3y^3=24

Divide both sides by 3.

y^3=8

Taking cube root on both sides.

y=2

So, y=2 at x=-1.

Differentiate (i) with respect to t.

4(2x\dfrac{dx}{dt})+3(3y^2\dfrac{dy}{dt})=0

Putting x=-1, y=2 and \dfrac{dy}{dt}=8, we get

4(2(-1)\dfrac{dx}{dt})+3(3(2)^28)=0

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-8(\dfrac{dx}{dt}-9(4))=0

Divide both sides by -8.

\dfrac{dx}{dt}-36=0

\dfrac{dx}{dt}=36

Therefore, the value of 4x^2+3y^3=28 is 36.

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3 years ago
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