Ask question

Ask question

All categories

igor_vitrenko [27]

3 years ago

8

You can mow your lawn in 2 hours. Your friend can mow your lawn in 3 hours. How long will it take to mow your lawn if the two of

you work together?

2 answers:

Lemur [1.5K]3 years ago

3 0

It would take about 5 hours for them two to work together, because if you add 2+3 you will get 5 and they are asking in total.

Salsk061 [2.6K]3 years ago

3 0

It will take 2½ hours to mow the lawn

You might be interested in

Sophia pays $19.99 membership fee for an online music store. If sophia purchases n songs for $0.99 each write the expression for

Alona [7]

Answer:

The expression for the total cost is x = 19.99 + 0.99n .

Step-by-step explanation:

Let us assume that the total cost be x.

As given

Sophia pays $19.99 membership fee for an online music store.

If sophia purchases n songs for $0.99 each .

Than the expression becomes

Total cost = Membership fee + Cost of n songs

x = 19.99 + 0.99n

Here n represented the number of songs.

4 0

3 years ago

Arrange these readers from fastest to slowest Abel read 50 pages in 45 minutes Brian read 90 pages in 75 minutes and Charlie rea

lys-0071 [83]

Answer:

charlie,brian,abel

Step-by-step explanation:

7 0

3 years ago

Segment VY is a midsegment of trapezoid FEDC. Find x.

Morgarella [4.7K]

Answer:

x = 12

Step-by-step explanation:

The midsegment VY is half the sum of the parallel bases , that is

VY = $\frac{EF+CD}{2}$ , then

3x + 18 = $\frac{1}{2}$ (x + 96) ← multiply both sides by 2 to clear the fraction

6x + 36 = x + 96 ( subtract x from both sides )

5x + 36 = 96 ( subtract 36 from both sides )

5x = 60 ( divide both sides by 5 )

x = 12

8 0

2 years ago

F (n) = 65 - 100n<br> f (39) =

yan [13]

f(39)=65-100(39)

65-3900

= -3835

6 0

2 years ago

Maths functions question!!

Marina86 [1]

Answer:

5) DE = 7 units and DF = 4 units

6) ST = 8 units

$\textsf{7)} \quad \sf OM=\dfrac{3}{2}\:units$

8) x ≤ -3 and x ≥ 3

Step-by-step explanation:

<u>Information from Parts 1-4:</u>

brainly.com/question/28193969

$f(x)=-x+3$

$g(x)=x^2-9$

A = (3, 0) and C = (-3, 0)

<h3><u>Part (5)</u></h3>

Points A and D are the <u>points of intersection</u> of the two functions.

To find the x-values of the points of intersection, equate the two functions and solve for x:

$\implies g(x)=f(x)$

$\implies x^2-9=-x+3$

$\implies x^2+x-12=0$

$\implies x^2+4x-3x-12=0$

$\implies x(x+4)-3(x+4)=0$

$\implies (x-3)(x+4)=0$

Apply the zero-product property:

$\implies (x-3)= \implies x=3$

$\implies (x+4)=0 \implies x=-4$

From inspection of the graph, we can see that the x-value of point D is <u>negative</u>, therefore the x-value of point D is x = -4.

To find the y-value of point D, substitute the found value of x into one of the functions:

$\implies f(-4)=-(-4)=7$

Therefore, D = (-4, 7).

The length of DE is the difference between the y-value of D and the x-axis:

⇒ DE = 7 units

The length of DF is the difference between the x-value of D and the x-axis:

⇒ DF = 4 units

<h3><u>Part (6)</u></h3>

To find point S, substitute the x-value of point T into function g(x):

$\implies g(4)=(4)^2-9=7$

Therefore, S = (4, 7).

The length ST is the difference between the y-values of points S and T:

$\implies ST=y_S-y_T=7-(-1)=8$

Therefore, ST = 8 units.

<h3><u>Part (7)</u></h3>

The given length of QR (⁴⁵/₄) is the difference between the functions at the same value of x. To find the x-value of points Q and R (and therefore the x-value of point M), subtract g(x) from f(x) and equate to QR, then solve for x:

$\implies f(x)-g(x)=QR$

$\implies -x+3-(x^2-9)=\dfrac{45}{4}$

$\implies -x+3-x^2+9=\dfrac{45}{4}$

$\implies -x^2-x+\dfrac{3}{4}=0$

$\implies -4\left(-x^2-x+\dfrac{3}{4}\right)=-4(0)$

$\implies 4x^2+4x-3=0$

$\implies 4x^2+6x-2x-3=0$

$\implies 2x(2x+3)-1(2x+3)=0$

$\implies (2x-1)(2x+3)=0$

Apply the zero-product property:

$\implies (2x-1)=0 \implies x=\dfrac{1}{2}$

$\implies (2x+3)=0 \implies x=-\dfrac{3}{2}$

As the x-value of points M, Q and P is negative, x = -³/₂.

Length OM is the difference between the x-values of points M and the origin O:

$\implies x_O-x_m=o-(-\frac{3}{2})=\dfrac{3}{2}$

Therefore, OM = ³/₂ units.

<h3><u>Part (8)</u></h3>

The values of x for which g(x) ≥ 0 are the values of x when the parabola is above the x-axis.

Therefore, g(x) ≥ 0 when x ≤ -3 and x ≥ 3.

8 0

1 year ago

Read 2 more answers