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vlada-n [284]
3 years ago
5

8 is 1/6 of what number

Mathematics
2 answers:
charle [14.2K]3 years ago
6 0

8 is 1/6 of 8/6 = 1 1/3

125 is 5/10 of 625/10 = 62 1/2

32 is 4/10 of 128/10 = 12 4/5

Vesna [10]3 years ago
5 0
8 is 1/6 of 48
125 is 5/10 of 250
32 is 4/10 of 80
192 is 4/5 of 240
396 is 6/8 of 528 ( I think)
11 is 1/5 of 55
72 is 3/5 of 120
360 is 6/10 of 600
I'll add the others later!
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Y=5-1/2x x=-2,0,2,4​
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Which is equivalent to 80^ 1/4
11Alexandr11 [23.1K]

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B) \sqrt[4]{80} ^x

Step-by-step explanation:

The given expression is 80^{\frac{1}{4} x}

It is 4th root. because 1/4 represents the 4th root.

So, \sqrt[4]{80} ^x

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Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
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Step-by-step explanation:

8 0
3 years ago
If you start with 85 milligrams of Chromium 51, used to track red blood cells, which
zysi [14]

About 92 days are taken for 90 % of the material to <em>decay</em>.

The mass of radioisotopes (m), measured in milligrams, decreases exponentially in time (t), measured in days. The model that represents such decrease is described below:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} } (1)

Where:

  • m_{o} - Initial mass, in milligrams.
  • m(t) - Current mass, in milligrams.
  • \tau - Time constant, in days.

In addition, the time constant is defined in terms of half-life (t_{1/2}), in days:

\tau = \frac{t_{1/2}}{\ln 2} (2)

If we know that m_{o} = 85\,mg, t_{1/2} = 27.7\,d and m(t) = 8.5\,mg, then the time required for decaying is:

\tau = \frac{t_{1/2}}{\ln 2}

\tau = \frac{27.7\,d}{\ln 2}

\tau \approx 39.963\,d

t = -\tau \cdot \ln \frac{m(t)}{m_{o}}

t = -(39.963\,d)\cdot \ln \frac{8.5\,mg}{85\,mg}

t\approx 92.018\,d

About 92 days are taken for 90 % of the material to <em>decay</em>.

We kindly invite to check this question on half-life: brainly.com/question/24710827

8 0
2 years ago
HELP!!!!! ILL give brainliest rn
valentinak56 [21]

Answer:

Construct one angle bisector of the triangle

Step-by-step explanation:

 

8 0
2 years ago
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