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3 years ago

When the genetic material found within an offspring is diverse, what type of reproduction is responsible?

Biology

1 answer:

AnnZ [28]3 years ago

7 0

Answer:

sexual reproduction, because the genetic material comes from both parents.

Explanation:

The sperm and egg produced contain different combination of genes

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Samuel suffered damage to his temporal lobes during an operation to remove tumors from his brain. he is likely to have problems

Mila [183]

I believe the answer is Hearing

Temporal lobes are a major lobe of the cerebrum that located in the middle lower, between the frontal lobe and occipital lobe, below the parietal lobe. The main function of this lobe is to process the information that related to the sensory input of auditory, emotion, language and visual memory. Hearing/auditory problem would be the easiest sign to recognize.

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3 years ago

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In humans there is a dominant allele (A) for the absence of moles; while the recessive allele (a) results in the presence of mol

Art [367]

Answer:

a. $(p + q)^7$ = $p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7$

b. i. 0.75

ii. 0.000061

iii. 0.012

iv. 0.17

c. 0.67

Explanation:

a. The expansion of the binomial (p + q)7 would be such that:

$(p + q)^7$ = $p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7$

b. Both couples are heterozygous:

Aa x Aa

AA Aa Aa aa

Since A is dominant over a,

probability of having mole (aa) = 1/4

probability of not having moles = 3/4

Therefore, the probability of the first child not having moles = 3/4 or 0.75

ii. Let the probability of not having mole = p and the probability of having mole = q. From the binomial expansion:

$(p + q)^7$ = $p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7$

Probability that all of the children will have moles = $p^0q^7$

since p = 3/4 and q = 1/4

$p^0q^7$ = $(3/4)^0(1/4)^7$ = 0.000061

iii. Probability that the first two children will have no moles and the last five will have moles = $21p^2q5$

= $21(3/4)^2(1/4)^5$

= 0.012

iv. Probability that 4 will have no moles and 3 will have moles out of the 7 children = $35p^4q^3$

= $35(3/4)^4(1/4)^3$

= 0.17

c. Probability that the child born without moles is a carrier of the a-allele = probability of heterozygous.

From the cross in (b), the genotypes of those born without moles are AA and 2Aa. Therefore, the probability of not having moles and be Aa is:

= 2/3 or 0.67

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lyudmila [28]

Answer:

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The ________ is responsible for protein synthesis in a cell. dna polymerase proteosome rna polymerase ribosome ribozyme

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4 years ago

How do sulfur and phosphorus move from the biotic and abiotic pools during their cycles

ivolga24 [154]

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