If one mole of an unknown substance is 200.59 g/mole, what is the mass of 0.33 moles of that substance?
1 answer:
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Question - Write the net ionic equation for the reaction of sodium phosphate with iron (III) chloride. Include the complete ionic equation and label the spectator ions. Also be sure to label the reactants as products as solid, liquid, gas, or aqueous solutions
Answer:
P.S. The + and - are in parentheses because they are below the number.
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Answer:
-) 2-methylbut-2-ene
-) 2-methylbut-1-ene
-) 3-methylbut-1-ene
Explanation:
in this case, the hydration of alkenes is a <u>marknovnikov reaction</u>, this means that the "OH" group would be added in the <u>most substituted carbon</u> of the double bond. (Figure 1)
For 2-methylbut-2-ene the most substituted carbon is the <u>tertiary carbon</u> (the carbon in the right of the double bond), so we will obtain the desired molecule. In 2-methylbut-1-ene the most substituted carbon is again the <u>tertiary carbon</u> (the carbon in the bottom of the double bond), so we will obtain 2-methyl-2-butanol. Finally, for 3-methylbut-1-ene the carbocation would be formed on carbon 3, this is a secondary carbocation. We can obtain a most stable carbocation if we do a <u>hydride shift</u> (Figure 2). With this new molecule is possible to obtain 3-methylbut-1-ene.
