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3 years ago

What is the mass of a silver coin that contains 1.69x10^23 silver atoms? Report your answer in units of grams

Chemistry

1 answer:

Margaret [11]3 years ago

3 0

Answer: 30.27 g

Explanation:

Since the silver is in units of atoms, we have to use Avogadro's number and molar mass.

Avogadro's number: 6.022×10²³ atoms/mol

Molar Mass: 107.87 g/mol

Now that we have everything we need, we can convert atoms to grams.

$1.69*10^{23} atoms*\frac{1mol}{6.022*10^2^3 atoms} *\frac{107.87 g}{1mol} =30.27 g$

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3 years ago

Read 2 more answers

What is the specific heat capacity of an unknown metal if 75.00 g of the metal absorbs 418.6J of heat and the temperature rises

EleoNora [17]

Answer:

The specific heat capacity of the unknown metal is 0.223 $\frac{J}{g*C}$

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

In this case, you know:

Q= 418.6 J
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ΔT= 25 C

Replacing:

418.6 J= c* 75 g* 25 C

Solving:

$c=\frac{418.6 J}{75 g*25 C}$

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2 years ago

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I think it’s 4.5 x 10^9

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