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3 years ago

What is the mass of a silver coin that contains 1.69x10^23 silver atoms? Report your answer in units of grams

Chemistry

1 answer:

Margaret [11]3 years ago

3 0

Answer: 30.27 g

Explanation:

Since the silver is in units of atoms, we have to use Avogadro's number and molar mass.

Avogadro's number: 6.022×10²³ atoms/mol

Molar Mass: 107.87 g/mol

Now that we have everything we need, we can convert atoms to grams.

$1.69*10^{23} atoms*\frac{1mol}{6.022*10^2^3 atoms} *\frac{107.87 g}{1mol} =30.27 g$

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2 years ago

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