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shepuryov [24]
3 years ago
7

A band expects to put 16 songs on their next CD. The band writes and records ​50% more songs than they expect to put on the CD.

During the editing​ process, 50​% of the songs are removed. How many songs will there be on the final​ CD?
Mathematics
2 answers:
lara [203]3 years ago
8 0

Answer:

<u><em>12</em></u>

Step-by-step explanation:

Add 50% of 16 to 16, 50% of 16 is 0.5 * 16 = 8, 16 + 8 = 24

Multiply 24 by 50%, or 0.5 to get 12

MatroZZZ [7]3 years ago
4 0

Answer:

<u>12</u>

Step-by-step explanation:

16÷2=50% of 16

50% of 16 = 8

16 + 8 = 24

multiply 24 by 50% to get final answer- 12

therefore 12 songs were in the final CD. Lemme know if I’m wring, this would help me get better at answering. Thank you :).

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Answer:

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Step-by-step explanation:

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Sonbull [250]

\large\displaystyle\text{$\begin{gathered}\sf 9|x-8| < 36 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf Divide \ both \ sides \ by \ 9. \end{gathered}$}

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\large\displaystyle\text{$\begin{gathered}\sf Solve \ Absolute \ Value. \end{gathered}$}

  • \large\displaystyle\text{$\begin{gathered}\sf |x-8| < 4 \end{gathered}$}

\large\displaystyle\text{$\begin{gathered}\sf We \ know \ x-8 < 4 \ and \ x-8 > -4 \end{gathered}$}

<u>                                                                                                                             </u>

         \large\displaystyle\text{$\begin{gathered}\sf x-8 < 4 \ (Condition \ 1) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 < 4+8 \ (Add \ 8 \ to \ both \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x < 12 \end{gathered}$}

<u>                                                                                                                             </u>

           \large\displaystyle\text{$\begin{gathered}\sf x-8 > -4 \ (Condition \ 2) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x-8+8 > -4+8 \ (Add \ 8 \ to \ both \ \ sides) \end{gathered}$}\\\large\displaystyle\text{$\begin{gathered}\sf x > 4 \end{gathered}$}

<u>                                                                                                                             </u>

<u />\underline{\boldsymbol{\sf{Answer}}}

\boxed{\large\displaystyle\text{$\begin{gathered}\sf x < 12 \ and \ x > 4 \end{gathered}$} }

\large\displaystyle\text{$\begin{gathered}\sf Therefore,\bf{\underline{the \  correct \ option}} \  \end{gathered}$}\large\displaystyle\text{$\begin{gathered}\sf is \ \bf{\underline{"A"}}. \end{gathered}$}

6 0
2 years ago
Pls help answer....
emmainna [20.7K]

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5 0
3 years ago
a cone with radius of 3 feet and a height of 5 feet is placed on top of a cylinder as shown find the volume of the total figure
Darina [25.2K]

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Step-by-step explanation:

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To solve for the full volume including the cylinder, use the cylinder's volume formula.

Volume of a cylinder = height (pi) (r^2) and then add it to the 47.12.

Volume of a cone is pi(r^2)(h/3)

plug and chug!

h stands for height and r stands for radius.

5 0
2 years ago
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motikmotik

Answer:

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6 0
3 years ago
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