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Pavlova-9 [17]
2 years ago
5

-OL 18 3 * 1-10 - 4 19 9 10 LIA EP 1000

Mathematics
1 answer:
Deffense [45]2 years ago
5 0

Answer:

The asnwer is 19

Step-by-step explanation:

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16. Find the values of x and y. (2y + 5) (5x - 17) (3x – 11)º
Iteru [2.4K]

Answer:

x = 26

y = 9

Step-by-step explanation:

(5x - 17)° + (3x - 11)° = 180° (angles in a straight line)

Solve for x

5x - 17 + 3x - 11 = 180

Collect like terms

5x + 3x - 17 - 11 = 180

8x - 28 = 180

Add 28 to both sides

8x = 180 + 28

8x = 208

Divide both sides by 8

x = 208/8

x = 26

Also:

(2y + 5)° + 90° + (3x - 11)° = 180° (angles on a straight line)

Plug in the value of x and solve for y

2y + 5 + 90 + 3(26) - 11 = 180

2y + 5 + 90 + 78 - 11 = 180

Collect like terms

2y + 162 = 180

Subtract 162 from both sides

2y = 180 - 162

2y = 18

y = 9 (dividing both sides by 2)

3 0
3 years ago
Write an algebraic expression to represent the phrase the different between two times b & 11
svet-max [94.6K]

are you sure you wrote that right?????

6 0
3 years ago
WHAT IS 4,876 DIVIDED BY 76?<br><br><br> i in 3rd grade doing advanced wok, i need help!
klio [65]

Answer:

64.1578

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
In Tucson, Arizona, the air pollution index averages 62.5 during the year with a standard deviation of 18. assuming normality, t
andrew-mc [135]
The interval of 95% confidence, for normally distributed variables, is average +/- 2 * standard deviation:

(-2*standard deviation + average , average + 2*standard deviation)

(-2*18 + 62.5 , 2*18 + 62.5) = (-36 + 62.5 , 36 + 62.5) = (26.5 , 98.5)

Answer: option D)


8 0
2 years ago
Sum of series to n terms 0.4+0.44+0.444+....
svetoff [14.1K]
0.4+0.44+0.444+\cdots=\dfrac4{10}+\dfrac{44}{100}+\dfrac{444}{1000}+\cdots=\displaystyle\sum_{k=1}^\infty\frac{\frac49(10^k-1)}{10^k}=\frac49\sum_{k=1}^\infty\left(1-\frac1{10^k}\right)

The nth partial sum is given by

S_n=\displaystyle\frac49\sum_{k=1}^n\left(1-\frac1{10^k}\right)
S_n\displaystyle=\frac49\bigg(\left(1-\frac1{10}\right)+\left(1-\frac1{100}\right)+\cdots+\left(1-\frac1{10^{n-1}}\right)+\left(1-\frac1{10^n}\right)\bigg)
S_n=\dfrac49\left(n-\dfrac{10^n-1}{9\times10^n}\right)=\dfrac4{81}(9n-1+10^{-n})

from which it follows that the infinite sum does not converge.
8 0
3 years ago
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