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kaheart [24]
2 years ago
7

48 inches 32 inches 18. Inches What is the area of the building front?

Mathematics
1 answer:
jarptica [38.1K]2 years ago
7 0
48 inches is the area in the front of the building
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5) A cube has height of 3 cm. What is the volume of the cube?
ElenaW [278]

Answer:

V =27cm^3

Step-by-step explanation:

The volume of a cube is given by

V = s^3 where s is the side length

V = 3^3

V = 3^3

V =27cm^3

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3 years ago
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Is -1 ft greater than -5ft
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Answer:

yes

Step-by-step explanation:

-1ft is greater then -5ft

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Use the inequality symbol to compare 5+(-4)____________14+(-13)
Margarita [4]
Both inequality is different positive and negative and it would be
6 0
3 years ago
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A spaceship is traveling at a steady rate. The table shows the distance the spaceship travels in a given period of time. Find th
nika2105 [10]

The distance of the spaceship in discuss as in the task content given can be evaluated as; 800miles.

<h3>What is the distance the spaceship travels in 4 minutes?</h3>

The distance travelled by the spaceship in discuss can be evaluated by means of the slope of the linear relationship as follows;

Hence it follows from ratios that by observation, the linear relationship has a slope of 200mi/min.

Consequently, we can evaluate the distance travelled after 4 minutes as;

Distance = 200 × 4 = 800mi.

Ultimately, the distance travelled per minute by the spaceship is; 800mi.

Remarks:

600 miles

520 miles

800 miles

1,080 miles

Read more on ratios;

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4 0
2 years ago
Salaries of 49 college graduates who took a statistics course in college have a​ mean, x overbar​, of $ 65 comma 300. Assuming a
Molodets [167]

Answer: 60,540< \mu

Step-by-step explanation:

The confidence interval for population mean is given by :-

\overline{x}-z^*\dfrac{\sigma}{\sqrt{n}}< \mu

, where \sigma = Population standard deviation.

n= sample size

\overline{x} = Sample mean

z* = Critical z-value .

Given :  \sigma=\$17,000

n= 49

\overline{x}= \$65,300

Two-tailed critical value for 95% confidence interval = z^*=1.960

Then, the 95% confidence interval would be :-

65,300-(1.96)\dfrac{17000}{\sqrt{49}}< \mu

=65,300-(1.96)\dfrac{17000}{7}< \mu

=65,300-4760< \mu

=60,540< \mu

Hence, the 95​% confidence interval for estimating the population mean (\mu) :

60,540< \mu

7 0
3 years ago
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