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o-na [289]
3 years ago
9

Given mZ1= x° and m Z2 = (x +50)".

Mathematics
1 answer:
Tju [1.3M]3 years ago
5 0

Given:

m∠1= x° and m∠2 = (x +50)°.

To find:

The value of x, m∠1 and m∠2.

Solution:

From the figure it is clear that, transversal side intersect the opposite sides which are parallel and form ∠1 and ∠2.

Sum of same sided interior angles is 180 degrees. So,

m\angle 1+m\angle 2=180^\circ

x^\circ+(x+50)^\circ=180^\circ

2x^\circ+50^\circ=180^\circ

2x^\circ=180^\circ-50^\circ

2x^\circ=130^\circ

Divide both sides by 2.

x^\circ=65^\circ

x=65

Now,

m\angle 1=65^\circ

m\angle 2=(65+50)^\circ=115^\circ

Therefore, the correct option is C.

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3 years ago
Solve the equation y = 200 - 5(x + 37) for x if y = 360.
julsineya [31]

Answer:

x= -35.153846

Step-by-step explanation:

360=200-5(x+37)

360=195(x+37)

360=195x+7215

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7 0
3 years ago
if p(x) = x+ 7/ x-1 and q (x) = x^2 + x - 2, what is the product of p(3) and q(2)? a. 50 b. 45 c. 40 d. 20 e. 6
Amanda [17]

Answer:

d. 20

Step-by-step explanation:

To answer the question given, we will follow the steps below:

we need to first find p(3)

p(x) = x+ 7/ x-1

we will replace all x by 3 in the equation above

p(3) = 3+7 / 3-1

p(3) = 10/2

p(3) = 5

Similarly to find q(2)

q (x) = x^2 + x - 2,

we will replace x by 2 in the equation above

q (2) = 2^2 + 2 - 2

q (2) = 4 + 0

q (2) = 4

The product of p(3) and q(2)   =   5 × 4   = 20

6 0
3 years ago
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