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Dvinal [7]
3 years ago
9

Monthly sales of water heaters are normally distributed with a mean of 21 and a standard deviation of 5. What is the probability

of selling 12 water heaters or
less?
a) 3.59%
Ob) 1.8096
O c) 96.41%
O d) 8.45%
Mathematics
1 answer:
mina [271]3 years ago
4 0

Answer:

Option A: 3.59% is the correct answer

Step-by-step explanation:

Z-score is used to calculate the probabilities when mean and standard deviation is given.

Given

Mean = μ = 21

SD = σ = 5

We have to find the probability of selling 12 or less water heaters so our x value is 12

x = 12

The z-score of a value is calculated as:

z-score = (x-μ)/σ

Putting the values

z-score=\frac{12-21}{5} \\=\frac{-9}{5}\\=-1.8

Now z-score table will be used to calculate the probability for z= -1.8

So we will go for the row with -1.8 and column 0, which gives us: 0.03593

As we have to calculate the probability in percentage

=0.03593*100\\= 3.593\%

Hence,

Option A: 3.59% is the correct answer

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Given

\frac{10q^5w^7}{2w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Required

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\frac{5q^5w^7}{w^3}.\ \frac{4\left(q^6\right)^2}{w^{-5}}

Apply law of indices on the first fraction;

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