Question 19 True/False Worth 1 points)

1 answer:

3 0

True because you can draw one short line and one long line an equal distance apart and then connect the parallel lines with slanted lines

You might be interested in

5( 5X – 10) = 15 solve it

olga55 [171]

5(5x-10)=15
5x-10=3
5x=10+3
5x=13
Divide both sides by 5-5 and 5 cancel out to leave you with x 13/5 =2.6
X=2.6

5 0

3 years ago

ILL GIVE BRAINLIEST PLS HELP ASAP

Lostsunrise [7]

Answer:

is the answer 12? i got the answer 12

3 0

2 years ago

Read 2 more answers

Find the x-coordinates of any relative extrema and inflection point(s) for the function f(x)= 6x^1/3 + 3x^4/3. You must justify

irina [24]

Answer:

x-coordinates of relative extrema = $\frac{-1}{2}$

x-coordinates of the inflexion points are 0, 1

Step-by-step explanation:

$f(x)=6x^{\frac{1}{3}}+3x^{\frac{4}{3}}$

Differentiate with respect to x

$f'(x)=6\left ( \frac{1}{3} \right )x^{\frac{-2}{3}}+3\left ( \frac{4}{3} \right )x^{\frac{1}{3}}=\frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}$

$f'(x)=0\Rightarrow \frac{2}{x^{\frac{2}{3}}}+4x^{\frac{1}{3}}=0\Rightarrow x=\frac{-1}{2}$

Differentiate f'(x) with respect to x

$f''(x)=2\left ( \frac{-2}{3} \right )x^{\frac{-5}{3}}+\frac{4}{3}x^{\frac{-2}{3}}=\frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}\\f''(x)=0\Rightarrow \frac{-4x^{\frac{2}{3}}+4x^{\frac{5}{3}}}{3x^{\frac{2}{3}}x^{\frac{5}{3}}}=0\Rightarrow x=1$