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1 answer:
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Hello!
We have the following expression:
Let's multiply and simplify it, look:
We multiply a*a*a, so we can rewrite it as a³. The same with b*b as b².
So, the answer in the simplified form is:
6a³ + 4b²
Answer:
x^4 -53x^2 +108x +160
Step-by-step explanation:
If <em>a</em> is a zero, then (<em>x-a</em>) is a factor. For the given zeros, the factors are ...
p(x) = (x +8)(x +1)(x -4)(x -5)
Multiplying these out gives the polynomial in standard form.
= (x^2 +9x +8)(x^2 -9x +20)
We note that these factors have a sum and difference with the same pair of values, x^2 and 9x. We can use the special form for the product of these to simplify our working out.
= (x^2 +9x)(x^2 -9x) +20(x^2 +9x) +8(x^2 -9x) +8(20)
= x^4 -81x^2 +20x^2 +180x +8x^2 -72x +160
p(x) = x^4 -53x^2 +108x +160
_____
The graph shows this polynomial has the required zeros.
Answer:
See attachment :D
Step-by-step explanation:
y = 2/3x + 2
This is in slope-intercept form, y = mx+b. m is the slope, 2/3, and b is the y- intercept, 2. So you know the line intersects with the y-axis at (0,2). The slope is 2/3. So you can move up two points, then over three. Because it's a positive slope, you move right. This leaves you at point (0,3). Connect a line between these two points.
The line intersects with points (-3,0) and (0,2).
Hope this is helpful ^^ Good luck with your test :D
