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3 years ago

Pls help me plssssssssssss

Mathematics

1 answer:

natka813 [3]3 years ago

8 0

Answer:

Step-by-step explanation:

the aswer is d

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Lyle bought 3/8 pound of red grapes and 5/12 of green grapes. How many pounds of grapes did he buy ?

STatiana [176]

He bought 19/24 pounds of grapes.
You need to find the common denominators then add.

3/8 = 9/24 - Red grapes
5/12 = 10/24 - Green grapes

10/24 + 9/24 = 19/24.
Therefore, he bought 19/24 pounds of grapes.
Hope this helped! :-)

6 0

3 years ago

What is the inverse of the function h(x)=5+x/4-2x

deff fn [24]

Answer:

I believe you, Divide x x by 1 1 .

Step-by-step explanation:

Since g(h(x))=x g ( h ( x ) ) = x , h−1(x)=2x5−85 h - 1 ( x ) = 2 x 5 - 8 5 is the inverse of h(x)=52x+4 h ( x ) = 5 2 x + 4 .

sorry if im wrong

4 0

3 years ago

Someone please help??

Xelga [282]

Answer:

x-axis

Step-by-step explanation:

The asymptote is a straight line that the curve gets closer and closer to but never touches it.

The given exponential function is $f(x)=3^x$ .

The given graph has a horizontal asymptote,

The equation of this horizontal asymptote is y=0.

This is also refers to as the x-axis.

Therefore the asymptote is the x-axis.

6 0

3 years ago

Given the following two statements, is the compound statement valid? p: Two angles are congruent. q: The angles are vertical Com

maw [93]

No, this is not valid. In the picture below, $\angle a$ is a vertical angle with $\angle b$ . But $\angle a$ is not $\cong \angle b$

5 0

2 years ago

A rectangular parking lot has a perimeter of 384 meters. The length of the parking lot is 36 meters less than the width. Find th

-Dominant- [34]

Answer:

The length and width of the parking lot is 78 meters and 114 meters respectively.

Step-by-step explanation:

Given;

Perimeter of the parking lot = $384\ m$

Solution,

Let the width of the parking lot be x.

Then, according to question length = (x-36).

The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;

$perimeter=2\times(length+width)$

Now substituting the values, we get;

$384=2\times(x-36+x)\\\frac{384}{2}=(2x-36)\\192=2x-36\\192+36=2x\\2x=228\\x=\frac{228}{2}= 114$

Width = $114\ m$

Length = $x-36=114-36=78\ m$

Hence the length and width of the parking lot is 78 meters and 114 meters respectively.

6 0

2 years ago