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4 years ago

What is the value for x?

Mathematics

2 answers:

Bumek [7]4 years ago

7 0

Answer:

BRAINLIEST PLZZZ

Step-by-step explanation:

5=x. angles a and c are equivalent, so you just add them together and subtract from 180, then solve for x plugging in difference of the two.

taurus [48]4 years ago

5 0

Step-by-step explanation:

angle B=6x+4

6x=4

x=4/6

x=0.6

..I got this much...sorry if its wrong

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Find the mean of the first five whole numbers

tiny-mole [99]

Answer:

Step-by-step explanation:

0+1+2+3+4= 10/5

= 2(mean of 1st 5 whole numbers)

3 0

3 years ago

Please help meee ASAP

Aliun [14]

The answer is B. 63 units

Explanation:

Perimeter is the outside of the shape, so you have to add up all the sides.

13+9+8+5+4+13+5+6=63

Perimeter= 63 units

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3 years ago

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Simplify the expression (1.25 x 107) (4 x 104).<br> HELPP

ankoles [38]

Answer:

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Step-by-step explanation:

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3 years ago

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What is the solution to 5p - 9 = 2p + 12

a_sh-v [17]

Answer:

p = 7

Step-by-step explanation:

Step 1: Subtract 2p from both sides.

5p − 9 − 2p = 2p + 12 − 2p

3p − 9 = 12

Step 2: Add 9 to both sides.

3p − 9 + 9 = 12 + 9

3p=21

Step 3: Divide both sides by 3.

$\frac{3p}{3}$ = $\frac{21}{3}$

p = 7

3 0

4 years ago

An experiment involves 17 participants. From these, a group of 3 participants is to be tested under a special condition. How man

lakkis [162]

Answer: 680

Step-by-step explanation:

When order doesn't matter,then the number of combinations of choosing r things out of n = $^nC_r=\dfrac{n!}{r!(n-r)!}$

Given: Total participants = 17

From these, a group of 3 participants is to be tested under a special condition.

Number of groups of 3 participants chosen = $^{17}C_3=\dfrac{17!}{3!(17-3)!}\$

$^{17}C_3=\dfrac{17!}{3!(17-3)!}\\\\=\dfrac{17\times16\times15\times14!}{3\times2\times14!}\\\\=680$

Hence, there are 680 groups of 3 participants can be chosen,.

8 0

4 years ago