Question

What is the length of u and v in this 30-60-90 triangle

Answer 1

Answer:

option 2

Step-by-step explanation:

Using trigonometric ratio:

$Cos \ 60 = \frac{adjacent } {hypotenuse} \\\\\frac{1}{2} = \frac{4}{u}\\\\1 \times u = 2 \times 4 \\\\u = 8$

Now using Pythagoras theorem we will find v

$8^2 = 4^2 + v^2\\\\64 = 16 + v^2\\\\v^2 = 64 - 16 \\\\v = \sqrt{48} = \sqrt{16 \times 3} = \sqrt{4^2 \times 3 } = 4\sqrt{3}$