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ivanzaharov [21]
3 years ago
8

What is the value of x? х 6v2 45°

Mathematics
2 answers:
SpyIntel [72]3 years ago
8 0

Answer:

100

Step-by-step explanation:

g

Anna35 [415]3 years ago
8 0
6v2xv2: 12 x=12 olmalı
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The length of each side of a square is 3 inches more than the length of each side of a smaller square the sum of the areas of th
Svetradugi [14.3K]
The length of each side of a square is 3 in. more than the length of each side of a smaller square. The sum of the areas of the squares is 149 in. $^{2} .$ Find the lengths of the sides of the two squares.
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3 years ago
PLEASE HELP
slavikrds [6]

Answer:

B. Yes! Jason has printed 73/100 of the posters needed.

Step-by-step explanation:

7/10(1500) = 1050 minimum to print

1500-400 = 1100 printed

1100/1500 = 73/100

7 0
3 years ago
Please help I'm behind
inessss [21]

You applied the rule improperly.  When dividing exponents, you subtract the exponent of the denominator <em>from</em> the exponent of the numerator, not the other way around.  The exponent you should have gotten was 8^{-6}

8 0
2 years ago
which of the following questions (multiple answers) are the square roots for 529? check all that applies please I've been stuck
mr Goodwill [35]
23 is one of the answers, and -23, because negative times negative is positive.

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4 0
3 years ago
Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior citizen tickets and 4 child ticke
FrozenT [24]

Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?

14S + 4C = 200

14S = 200 - 4C

S = (200 - 4C)/14

7S + 1C = 92

7S = 92 - C

S = (92 - C)/7

(200 - 4C)/14 = (92 - C)/7

7 x (200 - 4C) = 14 x (92 - C)

1400 - 28C = 1288 - 14C

1400 - 1288 = 28C - 14C

112 = 14C

C = 112/14 = 8

the price of one child ticket = $8

8 0
3 years ago
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