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3 years ago

What is the greatest common factor of 35 56 and 63?

Mathematics

1 answer:

Arada [10]3 years ago

3 0

7 is the answer...
because 7*5=35
7*8=56
7*9=63
hope this helps.......:)

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Lot the numbers on the number line.

Sergio039 [100]

Answer

$\sqrt{5} < 3, and, \sqrt{8} < \sqrt{13}, and, 2.2$

Step-by-step explanation:

If doing e2020 on the lesson "Estimating and Comparing Square Roots"

You estimate lower and lower until you get your exact point.

3 0

3 years ago

Read 2 more answers

Hallar el menor número no divisible por 4, 6, 9, 11 y 12, tal que al dividirlo por estos números se obtengan restos iguales.

Aloiza [94]

Answer:

397

Step-by-step explanation:

Sea 'p (x)' el número que no es divisible por 4, 6, 9, 11 y 12 de manera que cuando se divide por estos números da un resto igual, tenemos;

Por teorema del resto, tenemos;

p (x) = (x - a) · Q (x) + R

Dónde;

p (x) = El número, que se divide

Q (x) = El cociente

(x - a) = El divisor

R = El resto

Dado que el número más pequeño es 4, el resto, 0 <R <4

Para el número entero más pequeño arriba (x - a) · Q (x), tenemos;

R = 1

Observamos que el mínimo común múltiplo de 4, 6, 9, 11 y 12 = 396, por lo tanto, podemos tener;

(x - a) · Q (x) = 396

R = 1, dar;

p (x) = 396 + 1 = 397

Por lo tanto;

El número que no es divisible por 4, 6, 9, 11 y 12, de manera que cuando se divide por estos números da residuos iguales, p (x) = 397

7 0

3 years ago

Would it be 4? Or would I do 1 divided by four

Lunna [17]

Answer:

k = 4

Step-by-step explanation:

The graph represents y and x in direct proportion with equation

y = kx ← k is the constant of proportionality

To find k use the point (1, 4), that is x = 1, y = 4

k = $\frac{y}{x}$ = $\frac{4}{1}$ = 4

7 0

3 years ago

Given: P is a point on the perpendicular bisector, I of MN.<br> Prove: PM = PN

Hatshy [7]

Answer:

Step-by-step explanation:

I can't make specific statements about the proof because the midpoint is missing.

Givens

There are two right angles created by where the perpendicular bisector meats MN. Both are 90 degrees.

MN is bisected by the point on MN where the perpendicular meets MN

The Perpendicular Bisector is is common to both triangles.

Therefore the two triangles are congruent by SAS

PM = PN Parts contained in Congruent triangles are congruent.

5 0

3 years ago

Which of the following gives a valid reason for using the given solution method to solve the system of equations shown? Equation

alukav5142 [94]

Answer:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

Step-by-step explanation:

Equation I: 4x − 5y = 4

Equation II: 2x + 3y = 2

These equation can only be solved by Elimination method

Where to Eliminate x :

We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I

Hence:

Equation I: 4x − 5y = 4 × 2

Equation II: 2x + 3y = 2 × 4

8x - 10y = 20

8x +12y = 6

Therefore, the valid reason using the given solution method to solve the system of equations shown is:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

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3 years ago