Answer:
OBTUSE
Step-by-step explanation:
You would first have to figure this put via Pythagorean theroem. Basically do this (attachment)***C IS THE LARGEST NUMBER*** and know that c^2 < a^2 + b^2 (less than) = ACUTE, c^2 > a^2 + b^2 (greater than) = OBTUSE, and c^2 = a^2 + b^2 is RIGHT. If it is Right with all different numbers, it is SCALENE.
They have collected
cans until now. To equal 325, they need
cans more.
A.
Let C be the number needed to equate atleast 325.

B.
If we solve the inequality in part A, we can find minimum number of C to meet the goal of 325 cans.

<em>So they need minimum 101 to complete the target and more than that to surpass.</em>
ANSWER: 101 cans are needed to meet the goal and more than that to surpass the goal.
3x + 6 + 4 = 6 × 2 + 10
3x + 6 + 4 = 12 + 10
3x + 10 = 12 + 10
3x + 10 = 22
3x = 22 - 10
3x = 12
x = 12/3
x = 4
The answer is: x = 4.
I think the correct answer from the choices listed above is option A. The expenses that are discretionary would be clothes. <span>A </span>discretionary expense<span> is a cost which is not essential for the operation of a home or a business. Hope this answers the question. Have a nice day.</span>
Answer:
Step-by-step explanation:
Given
Circle has radius 
Area of the sector is given by

if
is one-sixth of area of circle then



If
is one-fourth of area of circle then


