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Gre4nikov [31]
3 years ago
5

Dalle note 3 green 1 we ame 7 vel maps on abier med up and make one of the

Mathematics
1 answer:
Zina [86]3 years ago
8 0

Answer:

I have no idea what this means

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How can i factorise <img src="https://tex.z-dn.net/?f=12x%20-%206" id="TexFormula1" title="12x - 6" alt="12x - 6" align="absmidd
Lorico [155]

Answer:

6(2x - 1)

Step-by-step explanation:

Given

12x - 6 ← factor out common factor of 6 from both terms

= 6(2x - 1) ← in factored form

8 0
3 years ago
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Miss Garner has 69 gold stickers. She wants to give the same number of stickers to each of her 15 students. If she gives away as
Hatshy [7]

Answer: 69/15=4 and remainder 9

Step-by-step explanation: Since 15 x 4 = 60, 15 can't go into 9 so 9 in the leftover

7 0
3 years ago
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A student needed to prepare 500mL of 1X TAE buffer to run a QC gel. The stock solution in the lab is 5X TAE. What volumes of sto
Xelga [282]

Answer:

you need 100ml of 5X TAE and 400ml of water.

Step-by-step explanation:

You need to use a rule of three:

C_1V_1=C_2V_2

where:

\left \{ {{C_1= 5X} \atop {C_2=1X}} \right.

and

\left \{ {{V_1 = V_{TAE}} \atop {V_2=500ml}} \right.

Therefore:

V_{TAE} = \frac{V_2*C_2}{C_1}

V_{TAE} = 100ml

Then just rest the TAE volume to the final Volume and you get the amount of water that you need to reduce the concentration.

3 0
2 years ago
Read 2 more answers
What the simplest radical form of square root of 50 is
vekshin1
The answer to this is 5√2
3 0
3 years ago
Secants L J and L M intersect and form an angle at point L. Solve for x.
german

Answer:

x = 14  

Step-by-step explanation:

Assume your diagram is like the one below.

The intersecting secant angles theorem states, "When two secants intersect outside a circle, the measure of the angle formed is one-half the difference between the far and the near arcs."

For your diagram, that means

\begin{array}{rcl}m\angle L &=&\dfrac{1}{2} \left(m \widehat {JM} - m\widehat {PQ}\right)\\\\(3x + 13)^{\circ}& = &\dfrac{1}{2} \left[(8x + 48)^{\circ} - (5x - 20)^{\circ}\right]\\\\3x + 13& = &\dfrac{1}{2}(8x + 48 - 5x + 20)\\\\3x + 13& = &\dfrac{1}{2}(3x + 68)\\\\6x + 26 & = & 3x + 68\\6x & = & 3x + 42\\3x & = & 42\\x & = & \mathbf{14}\\\end{array}

Check:

\begin{array}{rcl}(3\times14 + 13) & = &\dfrac{1}{2} \left[(8\times14 + 48)^{\circ} - (5\times14 - 20)^{\circ}\right]\\\\42 + 13& = &\dfrac{1}{2}(112 + 48 - 70 + 20)\\\\55& = &\dfrac{1}{2}(110)\\\\55 & = & 55\\\end{array}

It checks.

6 0
3 years ago
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