Answer: 
Step-by-step explanation:
Logarithms are in the format
while exponential form is in the format 
So we can transfer a,b, and c from the log form to the exponential form

Answer:
Step-by-step explanation:
I'm sure you want your functions to appear as perfectly formed as possible so that others can help you. f(x) = 4(2)x should be written with the " ^ " sign to denote exponentation: f(x) = 4(2)^x
f(b) - f(a)
The formula for "average rate of change" is a.r.c. = --------------
b - a
change in function value
This is equivalent to ---------------------------------------
change in x value
For Section A: x changes from 1 to 2 and the function changes from 4(2)^1 to 4(2)^2: 8 to 16. Thus, "change in function value" is 8 for a 1-unit change in x from 1 to 2. Thus, in this Section, the a.r.c. is:
8
------ = 8 units (Section A)
1
Section B: x changes from 3 to 4, a net change of 1 unit: f(x) changes from
4(2)^3 to 4(2)^4, or 32 to 256, a net change of 224 units. Thus, the a.r.c. is
224 units
----------------- = 224 units (Section B)
1 unit
The a.r.c for Section B is 28 times greater than the a.r.c. for Section A.
This change in outcome is so great because the function f(x) is an exponential function; as x increases in unit steps, the function increases much faster (we say "exponentially").
Answer:
(0,0)
Step-by-step explanation:
If the line is crossing the origin then that means both the x and y intercepts are (0,0)
What is the square root of 999,999,999,999,999,999,999,999,999,999,999
zheka24 [161]
Answer:
3.1622777e+16
Step-by-step explanation:
3 *4 12 have
- =
7 *4 28 total
28-12=16