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BigorU [14]
3 years ago
7

Will give brainliest

Mathematics
1 answer:
kow [346]3 years ago
8 0

Answer:

b-

Step-by-step explanation:

choose as brainliest

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A function, F(x), is shown below.
Maksim231197 [3]

Answer:

  range of f(x) = [-4, -2) ∪ [2, 8)

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Step-by-step explanation:

The graph is attached. The range is the vertical extent of the function. It is defined at f(0) = -4 and f(2) = 2.

The limits f(2-) and f(4-) are -2 and 8, respectively, so the graph has open circles there. These are the ends of the two half-open intervals that make up the range of the function.

The portion of the graph in the domain [4, 7) is included in the range [2, 8), so no special treatment is needed for that piece of the function.

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3 years ago
There are 8 times as many females as males on the maths course at university. What fraction
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4 0
3 years ago
Please explain how to do and set up
In-s [12.5K]

A

using the Cosine rule in ΔSTU

let t = SU, s = TU and u = ST, then

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substitute the appropriate values into the formula

t² = 5² + 9² - (2 × 5 × 9 × cos68° )

   = 25 + 81 - 90cos68°

   = 106 - 33.71 = 72.29

⇒ t = \sqrt{72.29} ≈ 8.5 in → A


6 0
3 years ago
Which national legislature has themost members?
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China has the most members.
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3 years ago
1. x=1/(root3-root2). find rootx-(1/rootx) 2. if x=[root(a+2b)+root(a-2b)]/[root(a+2b)-root(a-2b]. show that bx^2-ax+b=0
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1. x = 1/ ( \sqrt{3} -  \sqrt{2)} = \sqrt{3}+  \sqrt{2};
 ( \sqrt{x} -1/ \sqrt{x} )^{2} = x + 1/x - 2 = = 
6 0
3 years ago
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