Answer:
20 N
Explanation:
We can solve this problem by applying Newton's second law of motion, which states that the net force applied on an object is equal to the product between the mass of the object and its acceleration:
where
F is the net force
m is the mass
a is the acceleration
In this problem, we have:
m = 10 kg is the mass of the cart
is the acceleration
So the net force on the car is
Since Lucia and Akbar are pushing into opposite directions, this means that this net force is the resultant of the two forces: and since the cart is accelerating towards Akbar, this means that Lucia is applying a force 20 N stronger than Akbar.
Answer:
Explanation:
For this case we can use the following formula for the angular velocity:
where represent the final angular velocity , the initial angular velocity , t the time and the angular acceleration.
And for the linear acceleration we have this formula:
Where a represent the linear acceleration and the angular acceleration.
For this case the linear acceeleration is given
And the radius of the yo-yo is also given
So then we can use the following formula:
If we replace the values we got:
And solving for we got:
Answer:
The time it will take the car to travel the next 15 m is 1 s.
Explanation:
Given;
initial velocity of the car, u = 0
time of motion, t = 2.4 s
initial distance traveled, d = 15 m
determine the constant acceleration of the car;
d = ut + ¹/₂at²
15 = 0 + (0.5 x 2.4²)a
15 = 2.88a
a = 15 / 2.88
a = 5.21 m/s²
The velocity of the car at the end of the first 15 m
v - u + at
v = 0 + 5.21 x 2.4
v = 12.5 m/s
The time to cover the next 15 m;
d₂ = vt + ¹/₂at²
15 = 12.5t + (0.5 x 5.21)t²
15 = 12.5t + 2.61t²
0 = 2.61t² + 12.5t - 15
Use the formula method to solve the above quadratic equation.
a = 2.61
b = 12.5
c = -15
Therefore, the time it will take the car to travel the next 15 m is 1 s.
Answer: hello options related to your question is missing attached below is the missing part of your question
answer: No charge of the length of the bonds expected because the rod did not touch the charge source ( option A )
Explanation:
When the Charge is first, Furthest away and second and closest to the source charge. <em>The spring like bonds can be said to have No charge of the length of the bonds expected because the rod did not touch the charge source </em><em>when Furthest away the bond with charge will be less effective </em>