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polet [3.4K]
3 years ago
14

A specific amount of water would have the same mass even if you turned it from a liquid to a solid or a gas is an example of

Physics
2 answers:
Elena L [17]3 years ago
7 0

Answer:

b.Law of conservation of mass

mezya [45]3 years ago
6 0
I believe the answer is: B
(law of conservation of mass)
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True or False: Litmus paper turns blue in bases and red in acids. <br>True <br>False​
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If the graph represents speed, what is measured on the x and y axes? You need to specifically identify which axis is which.
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X axis - time
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The radius of Venus (from the center to just above the atmosphere) is 6050 km (6050✕103 m), and its mass is 4.9✕1024 kg. An obje
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Answer:

(a) The initial speed required is 13116 m/s

(b) The escape speed is 10394 m/s

This problem involves the application of newtons laws of gravitation. The forces in action here are conservative and as a result mechanical energy is conserved.

The full calculation can be found in the attachment below.

Explanation:

In both parts (a) and (b) the energy conservation equation were used. Assumption was made that when the object is very far from the planet the distance from the planet's center approaches infinity and the gravitational potential energy approaches zero.

The calculation can be found below.

6 0
3 years ago
Combine these three velocity vectors into a resultant: 3.0 m/s north, 4.0 m/s east 1.0 m/s west. Identify the resultant vector
Slav-nsk [51]

Answer:

The resultant vector is 1 m/s

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5 0
3 years ago
The electric field between square the plates of a parallel-plate capacitor has magnitude E. The potential across the plates is m
Helga [31]

Answer:

The magnitude of the electric field between the plates is half its initial value.

Explanation:

We know the electric field E = V/d where V = voltage applied and d = separation between plates.

Since V is constant and V = Ed,

So, E₁d₁ = E₂d₂ where E₁ = initial electric field at separation d₁, d₁ = initial separation of plates, E₂ = final electric field at separation d₂ and d₂ = final separation of plates.

So, E₂ = E₁d₁/d₂

Now, the distance between the plates is twice their original separation. Thus, d₂ = 2d₁

So, E₂ = E₁d₁/2d₁ = E₁/2

So, E₂ = E₁/2

Thus, the magnitude of the electric field between the plates is half its initial value.

5 0
3 years ago
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