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murzikaleks [220]
3 years ago
12

A 45.2 g sample of Silver at 101.0 ºC is dropped into 300.0 g of water at 30.6 ºC. What is the final temperature of the water?

Chemistry
1 answer:
saw5 [17]3 years ago
3 0

Answer:

Final temperature of water = 31.2° C

Explanation:

Let the final temperature of water be T degrees

Concept: By energy conservation law

Heat lost by the silver = heat gained by water

Heat lost be silver Q1 = m1c1ΔT1

Q1 = 45.2/1000Kg×2.36J/KgK×(101-T)

Heat gained by water Q2 = m2c2ΔT2

Q2 = 300/1000Kg×4.186J/KgK(T-30.6)

Since, Q1=Q2

⇒  45.2/1000Kg×2.36J/KgK×(101-T) = 300/1000Kg×4.186J/KgK(T-30.6)

Solving we get T = 31.2° C

Therefore, final temperature of water = 31.2° C

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