Answer:
-2.70 is the difference in the pH values of the two solutions.
Explanation:
Hydrogen ion concentration in solution A = ![[H^+]_A](https://tex.z-dn.net/?f=%5BH%5E%2B%5D_A)
Hydrogen ion concentration in solution B = ![[H^+]_B](https://tex.z-dn.net/?f=%5BH%5E%2B%5D_B)
The pH of solution A: pH
![pH=-\log[H^+]_A](https://tex.z-dn.net/?f=pH%3D-%5Clog%5BH%5E%2B%5D_A)
The pH of solution B: pH'
![pH'=-\log[H^+]_B](https://tex.z-dn.net/?f=pH%27%3D-%5Clog%5BH%5E%2B%5D_B)
![[H^+]_A=500\times [H^+]_B](https://tex.z-dn.net/?f=%5BH%5E%2B%5D_A%3D500%5Ctimes%20%5BH%5E%2B%5D_B)
![pH=-\log[500[H^+]}_B]](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B500%5BH%5E%2B%5D%7D_B%5D)
![pH=-\log[500]+(-\log[H^+]_B])](https://tex.z-dn.net/?f=pH%3D-%5Clog%5B500%5D%2B%28-%5Clog%5BH%5E%2B%5D_B%5D%29)
-2.70 is the difference in the pH values of the two solutions.
0.161 mols.
Balance the equation first
2Fe + O2 •••••> 2FeO
Find the molar masses of the compound
2(56) + 2(16) •••••> 2(56+16)
112g + 32g •••••> 144g
Fe reacting with O2
112g of Fe reacting with 32g of O2
18g of Fe reacting with x
x= 32×18/112
x= 5.143g
Amount= mass/ molar mass
Amount= 5.143g/32g
Amount= 0.161mls
I think it may be A but I’m not to certain
