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Phantasy [73]
3 years ago
7

Find the 40th term of the arithmetic sequence. a1 = 32, d = 8

Mathematics
2 answers:
____ [38]3 years ago
3 0
Hahahahaha A. 352 thats it yes
Effectus [21]3 years ago
3 0

Answer:the answer is 344. Not 352.

Step-by-step explanation:

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I need help...I'm new to all this geometry stuff can someone please show me some steps to this problem
Rasek [7]


There really aren't any steps. It's just a handy fact about Isosceles triangles.

An Isosceles triangle is a triangle that has two sides that are the same length,
and one of the facts about this kind of triangle is that the angles opposite the
two equal sides are equal angles.

In your picture, the two sides of the triangle that have tick marks across them
are equal lengths, and that means that the angles at 'S' and 'U' are equal angles.

In this kind of triangle, those are called the "base angles", even though they
don't necessarily have to be the angles that the triangle stands on.  They're
just the two angles that are opposite the two equal sides.


7 0
4 years ago
Read 2 more answers
In how many ways can you place 50 identical balls in six distinct urns such that each urn contains an odd number of balls
mezya [45]

Answer:

80730

Step-by-step explanation:

The answer is c(27,5)=27*26*25*24*23/5!. Here is why.

Let us solve a simpler problem. In how many ways 25 identical balls can be placed in six distinct urns such that no urn is empty?

25 balls in a row make 24 places for five dividers, so the answer is c(24,5).

2. Next problem. In how many ways 50 identical balls can be placed in six distinct urns such that no urn is empty and each urn contains even number of balls.

We group 50 balls in 25 pairs, so the answer is the same as in the previous problem which is

c(48/2,5)=c(24,5).

Let us denote the content of each urn as

u(1),u(2),…u(6). Note that each u(i) is even. Denote u(i) as u(i)=2k(i) where k is a natural number. We have

2k(1)+2k(2)+2k(3)+2k(4)+2k(5)+2k(6)=50.

3. Now let us proceed to the original problem where odd number of balls in each urn is required.

We have

2k(1)-1+2k(2)-1+2k(3)-1+2k(4)-1+2k(5)-1+2k(6)-1=50 or

2k(1)+2k(2)+2k(3)+2k(4)+2k(5)+2k(6)=56.

So the original problem reduces to previous problem where even number of balls in each urn is required but the total number of balls is 56 instead of 50.

Its answer is c(54/2,5)=c(27,5).

8 0
3 years ago
Please help? ♡ (20 pts!)
Alja [10]
Answer is C. \frac{a ^{8} }{b^{10} }
First start by subtracting the exponents from top to bottom
let's start with a  so a^2 - a^-2     2 - (-2) = 4
Now B: b^-3 - b^2   so -3 - 2 = -5
This leaves you with a^4 b^-5
However you cannot have a negative exponent so B must cross over and move to the bottom to become positive
Don't forget about the squared outside the parentheses. Both exponents must be multiplied by two to get 8 and 10
\frac{a^{4 x 2} }{b^{5 x 2} }
4 0
3 years ago
Read 2 more answers
The following question has two parts. First, answer part A. Then, answer part B.
Dmitriy789 [7]

Answer:

Her estimate is reasonable.She can make 25 completed centerpieces

Step-by-step explanation:

Estimate 20 flowers per centerpiece.  430 flowers divided by 20 flowers per centerpiece.

430 /20 is approximately 21 centerpieces.  Her estimate is reasonable.

430/20  Divide the top and bottom by 10

43/2  is  21*2 = 42   with 1 left over    21  1/2

We know we underestimated when we rounded 17 to 20.  Se we are a little under with 21.5


Exact answer:

430÷17

17 goes into 43  2 times  (17*2 = 34  43-34 =  9 left over)

17 goes into 90 5 time  (17*5 = 85  90-85 = 5 left over)

She can make 25 completed center pieces      

8 0
4 years ago
PLZZZ Help I don't understand this or know what to do!!!
vladimir2022 [97]

Answer:

The Answer Is C

Step-by-step explanation:

I had the same question, but i guessed and got it right c: hope this helps other people, even though its late to your question

3 0
3 years ago
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