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LiRa [457]
4 years ago
9

I need help...I'm new to all this geometry stuff can someone please show me some steps to this problem

Mathematics
2 answers:
Rudik [331]4 years ago
8 0
The two side with the lines that come out are equal. Which means the base is not the same as the two on the top of itself.
Rasek [7]4 years ago
7 0


There really aren't any steps. It's just a handy fact about Isosceles triangles.

An Isosceles triangle is a triangle that has two sides that are the same length,
and one of the facts about this kind of triangle is that the angles opposite the
two equal sides are equal angles.

In your picture, the two sides of the triangle that have tick marks across them
are equal lengths, and that means that the angles at 'S' and 'U' are equal angles.

In this kind of triangle, those are called the "base angles", even though they
don't necessarily have to be the angles that the triangle stands on.  They're
just the two angles that are opposite the two equal sides.


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wariber [46]

the ans is c=15/35t

hope it helps/can i get brainiest?

8 0
3 years ago
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Nancy has to find the coordinates of the reflection of the point across the y-axis. How can she find the coordinates of the new
oksian1 [2.3K]

Answer: (x, y) transforms into (-x, y)

Step-by-step explanation:

When we do a reflection over a given axis, the distance between the initial point to the axis must be the same as the distance of the reflected point to the axis.

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So if we start with the point (x, y), the only other point that is at the same distance from the y-axis is the point (-x, y)

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4 years ago
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What is the solution to this equation?
Scrat [10]
C X=6


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3 0
3 years ago
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The ratio of green pepper plants to red pepper plants in Joe's garden is 2:7. If Joe has 20 more red pepper plants than green pe
Marta_Voda [28]
I found that Joe has 28 red pepper plants and 8 green pepper plants.

to find this, I first set up a proportion:
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5 0
3 years ago
(02.05 MC)
Amiraneli [1.4K]

Table for f(x)

\boxed{\begin{array}{c|c}\boxed{\bf x}&\boxed{\sf f(x)}\\ \sf 0 &\sf 1 \\ \sf 2&\sf 9\\ \sf 4 &\sf 17\end{array}}

Table for g(x)

\boxed{\begin{array}{c|c}\boxed{\bf x}&\boxed{\sf g(x)}\\ \sf 0 &\sf 1 \\ \sf 2&\sf 7\\ \sf 4 &\sf 13\end{array}}

Option C is correct

3 0
3 years ago
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