A landscaper is making a garden bed in the shape of a rectangle. The length of the garden bed is 2.5 feet longer than twice the
width of the bed. The area of the garden bed is 62.5 square feet. What is the perimeter of the garden bed, in feet?
1 answer:
Answer:
I'll setup the problem, then you can do the calculations
Step-by-step explanation:
Perimeter = 2width(W) + 2length (L)
Area = LW
L = 2.5 + 2W
LW = 62.5
substitute L in equation for area
![2.5W + {2W}^{2} = 62.5 \\ \\ {2W}^{2} + 2.5 - 62.5 \\ \\ use \: quadratic \: solution \\\frac{ - b ± \sqrt{ {b}^{2} - 4ac}}{2a}](https://tex.z-dn.net/?f=2.5W%20%2B%20%20%7B2W%7D%5E%7B2%7D%20%20%3D%2062.5%20%5C%5C%20%20%5C%5C%20%20%7B2W%7D%5E%7B2%7D%20%20%2B%202.5%20-%2062.5%20%5C%5C%20%20%5C%5C%20%20use%20%5C%3A%20%20quadratic%20%5C%3A%20%20solution%20%5C%5C%5Cfrac%7B%20-%20b%20%C2%B1%20%20%5Csqrt%7B%20%7Bb%7D%5E%7B2%7D%20%20-%204ac%7D%7D%7B2a%7D%20)
a = 2; b = 2.5; c = 62.5
send a comment if you have a question
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