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madam [21]
3 years ago
13

Bubbles bakery has 24 oatmeal cookies, 36 vanilla bean cookies, 42 chocolate chip cookies. What is the greatest common factor bu

bbles bakery can use to divide the cookies into equal groups
Mathematics
1 answer:
STatiana [176]3 years ago
7 0

Answer:6

Step-by-step explanation:

We have three groups of cookies as follows:

24   oatmeal

36   vanilla bean

42  chocolate chip

If we breack down into factors we get

24    2       24 = 2³ * 3        36    2   36 = 2²*3³         42   2   42 = 2*3*7

12     2                                 18    2                              21   3

6      2                                   9    3                                7   7

3      3                                   3    3                                1

1                                             1

Fom where we can get that biggest common factor is 6

24 ÷  6      =  4

36 ÷  6      =  6

42 ÷  6      =  7

Then Bakery will have  4 groups of oatmeal cookies, 6 of vanilla bean, and 7 chocolate chip

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Step-by-step explanation:

Alright, lets get started.

Please refer the diagram I have attached.

The perimeter of the rectangle will be : 2\times(\ length+width)

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The perimeter will be : 10x+6

As per given question, the perimeter is given as 146 unit.

So,

10x+6=146

Subtracting 6 on both sides

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Plugging the value x in sides, the sides will be 2 \times 14=28 and

3 \times 14+3=45

Hence the length of the longer side is 45 units.   :   Answer

Hope it will help :)

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When we approach limits, we are finding values that are infinitesimally approaching this x-value. Essentially, we consider the approximate location that this root or limit appears. This is essential when it comes to taking Calculus, and finding the limit or rate of change of a function.

When we are attempting limits questions, there are several tests we attempt first.

1. Evaluate the limit by substituting the value of the x-value as it approaches the value (direct evaluation of a limit)
2. Rearrangement of the function, such that we can evaluate the limit.
3. (TRIGONOMETRIC PROPERTIES)
\lim_{x \to 0} (\frac{sinx}{x}) = 1
\lim_{x \to 0} (\frac{tanx}{x}) = 1
4. Using L'Hopital's Rule for indeterminate limits, such as 0/0, -infinity/infinity, or infinity/infinity.

For example:

1) \lim_{x \to 0}\frac{\sqrt{x} - 5}{x - 25}

We can do this using the first and second method.
<em>Method 1: Direct evaluation:</em>

Substitute x = 0 to the function.
\frac{\sqrt{0} - 5}{0 - 25}
= \frac{-5}{-25}
= \frac{1}{5}

<em>Method 2: Rearranging the function
</em>

We can see that x - 25 can be rewritten as: (√x - 5)(√x + 5)
By rewriting it in this form, the top will cancel with the bottom easily, and our limit comes out the same.

\lim_{x \to 0}\frac{(\sqrt{x} - 5)}{(\sqrt{x} - 5)(\sqrt{x} + 5)}
= \lim_{x \to 0}\frac{1}{(\sqrt{x} + 5)}}
= \frac{1}{5}

Every example works exactly the same way, and by remembering these criteria, every limit question should come out pretty naturally.
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