Write an equation in slope intercept form of the line that passes through (-2,10) and (1,1).

Mathematics

1 answer:

tamaranim1 [39]3 years ago

3 0

Answer:

Step-by-step explanation:

1st use the two points to find the slope of the line that passes thru those two points

m = y2 - y1 / x2 - x1

where point1 = ( x1, y1 ) and point2 = (x2, y2 )

your are given P1 = ( -2,10) and P2 = (1,1)

find the slope

m = 1-(-2) / 1-10

m = 1+2 / -9

m = 3 / -9

m = - 1/3

then use the point-slope formula [y-y1 = m(x-x1)] with either of the two points, I'll use P2 b/c it seems easier (1,1) , you get the same results with either point and work the problem to the slope-intercept form [y = mx +b ]

y -y1 = m(x-x1)

y-1 = -1/3(x-1)

y-1 = -1/3x + 1/3

y = -1/3x + 1/3 + 1

y = -1/3x + 4/3

:) got it ?

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4 years ago

A line passes through the points (4,6) and (6,2) .

siniylev [52]

ANSWER

Yes

No

No

Yes

EXPLANATION

The given line passes through the points,.
$(4,6) \: and \: (6,2)$

We need to determine the slope of this line using these two points.

The formula for finding the slope is

$m=\frac{y_2-y_1}{x_2-x_1}$

$m = \frac{2 - 6}{6 - 4} = - \frac{ - 4}{2} = - 2$

We can now use the formula

$y-y_1=m(x-x_1)$
in the slope intercept form.

If we use the point
$(4,6)$
the equation will be,

$y - 6 = - 2(x - 4)$

If we use the point,

$(6,2)$
we obtain,
$y - 2 = - 2(x - 6)$