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Likurg_2 [28]
3 years ago
10

8. Find the function rule. x : -2 | -1 | 0 | 1 | 2 | y : 9 | 4 | -1 | -6 | -11

Mathematics
1 answer:
goldenfox [79]3 years ago
8 0

Step-by-step explanation:

y = -5x - 1 should be your function.

Check. Plug in the x to get the desired y

9 = -5(-2) - 1

9 = 10 - 1

9 = 9 (correct)

4 = -5(-1) - 1

4 = 5 - 1

4 = 4 (correct)

-1 = -5(0) - 1

-1 = 0 - 1

-1 = -1 (correct)

etc.

~

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Determine la pendiente (m) de la recta que pasa por los puntos (2,3) y (- 2, - 4
labwork [276]
La pendiente de la recta que pasa por los puntos (2,3) y (-2,-4) es 7/4.

(2,3)      (-2,-4)
x₁ y₁       x₂  y₂

                y₂ - y₁       -4 -3           -7            7
              ----------- = --------- = ----------- = ------
                x₂ - x₁      -2 - 2           -4            4
                    ↑

                    ↑
la fórmula de el pendiente





5 0
4 years ago
What is the algebraic expression for f divided by 10
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Answer:

f ÷ 10

Step-by-step explanation:

We  want to write an expression

divided by means the number or variable before comes first, then the divided by symbol, then what comes after

f ÷ 10

7 0
2 years ago
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Question 1 of 10<br> What is the scale factor from RST to UVW?
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2 years ago
What are the Coefficients in 4e + 7e + 5
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7 0
3 years ago
50% of babies are born female Oliver wants to find the probability that 20 or more of the 50 babies born today were female if we
jarptica [38.1K]

Solution:

Number of babies which are female = 50%=\frac{1}{2}

So, if Population of 50 is considered , and 50% of population is female then  out of 25 must be female.

Population of female can't exceed 25.

Probability of an event = \frac{\text{Total favorable outcome}}{\text{Total Possible outcome}}

 Probability that 20 or more of the 50 babies born today were female

    =  _{20}^{50}\textrm{C}\times [\frac{1}{2}]^{20} \times [\frac{1}{2}]^{30}+_{21}^{50}\textrm{C}\times [\frac{1}{2}]^{21} \times [\frac{1}{2}]^{29}+_{22}^{50}\textrm{C}\times [\frac{1}{2}]^{22} \times [\frac{1}{2}]^{28}+_{23}^{50}\textrm{C}\times [\frac{1}{2}]^{23} \times [\frac{1}{2}]^{27}+_{24}^{50}\textrm{C}\times [\frac{1}{2}]^{24} \times [\frac{1}{2}]^{26}+ _{25}^{50}\textrm{C}\times [\frac{1}{2}]^{25} \times [\frac{1}{2}]^{25}

Simulation of the Above Situation

If we use a double sided coin and a sign heads us females and Tails as males,Toss the coin 50 times , number of times Heads comes shows number of females born and number of times tails appears shows Population of men.

It may not happen that Number of heads =Number of tails if we toss the coin 50 times.So if number of tosses increases the chances are more likely that , number of heads= Number of tails. But for above problem we just have to toss coin 50 times only, that is

Number of males = Number of females


8 0
4 years ago
Read 2 more answers
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