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Artyom0805 [142]
3 years ago
9

In the expression 9z + 3 - 2z + z - 2, how many constants are there

Mathematics
1 answer:
posledela3 years ago
4 0
There are two constants in this expression
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Expressão ( - b + c)² . h, para b = 12, c = 10 e h = 8, é: *<br>Mim ajudem ​
elena-14-01-66 [18.8K]

Answer:

i dont speak Spanish

Step-by-step explanation:

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3 0
3 years ago
A line has a slope of -4 and passes through the point (2,-5) <br> which is the equation of the line
dimulka [17.4K]

We will be using the Point Slope formula which is y-y_{1} =m(x-x_{1} )

The information we are given is that m = -4 and the point is (2,-5), so we can input it into the equation.

y- (-5) = -4(x-2)

This simplifies into y+5 = -4x +8

Then we can subtract 5 from each side to get the answer:

y = 4x+3

6 0
3 years ago
Find the area of the shaded region. round your answer to the nearest hundredth
Alex Ar [27]

Answer:

16 meters

Step-by-step explanation:

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5 0
3 years ago
Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans
zloy xaker [14]
Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.



Part B:

The area of the square is given by

Area=(x+4)^2=x^2+8x+16

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

x^2+8x+16=6x+8 \\  \\ \Rightarrow x^2+8x-6x+16-8=0 \\  \\ \Rightarrow x^2+2x+8=0 \\  \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2}  \\  \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2}  \\  \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>
7 0
3 years ago
PLZZZZZ HELP NEEDED ASAP WILL GIVE BRAINLIEST (IF RIGHT)
Harlamova29_29 [7]

x= 90° - 63° = 27° (NO perpendicular to AOB)

angle DOB = (90°+90°) -128° (angles on a straight line)

= 180° - 128°

= 52°

y= 180° - x - 63° - angle DOB (angles on a straight line)

=180° - 27° - 63° - 52°

= 38°

I'm not sure of the answer tho^^ good luck!

8 0
3 years ago
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