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inn [45]
3 years ago
5

During a cold front, the temperature in Denver, Colorado, dropped from 7 degrees C to -5 degrees C. What was the change in the t

emperature?
Mathematics
1 answer:
Radda [10]3 years ago
4 0

Answer:

-12 c

Step-by-step explanation:

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Someone please help on 43.
Bas_tet [7]

Answer: p=9.7

Step-by-step explanation:

40p+ 10.5p=489.85

50.5p=489.85

9.7=p

6 0
3 years ago
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HELP ASAP!!!! SO STUCK ON THIS! Will give brainliest IF CORRECT! :) please help! Be sure please!
vlada-n [284]
If I can read the #'s correctly:
add the yes answers together 23+147 = 170
add the no answers together 112+48= 160

so your ratio of haves to have nots is 170 to 160

but both sides can be divided by 10, so it can be simplified to 17 to 16.

Good Luck!
4 0
3 years ago
Read 2 more answers
Which letters Shown below on the number line also have their opposites labeled? (A- A and D) (B- B and C) (C- A B and C) (D- B C
anygoal [31]

try number 4 I thinks its that one or number 1

6 0
3 years ago
Sarah needs 10 feet of fabric for a project she is working on, but the store only sells the fabric in meters. One meter of fabri
Aleks [24]
<h2>Hello!</h2>

The answer is:

The fabric will cost $4.58

D.$4.58

<h2>Why?</h2>

Since it's a conversion exercise, we need to pay special attention to the conversion procedure.

From the statement we know that:

1ft=0.305m

So, if she needs 10 feet of fabric, we need to convert it to meters, and then, calculate its cost.

We have that:

10*1ft=10*0.305m\\\\10ft=3.05m

Now, we have that each meter of fabric cost $1.50, so, 3.05m of fabric will cost:

\frac{1m}{1.50(dollars)}=\frac{3.05m}{cost}\\\\cost=\frac{3.05m*1.50(dollars)}{1m}=4.575(dollars)=4.58(dollars)

Hence, we have that the cost of the fabric will be $4.58.

The correct option is: D.$4.58​

Have a nice day!

6 0
3 years ago
Use calculus to find the first order conditions. Use solver then to solve the first order conditions. Show your work for the fir
DaniilM [7]

The values of x and y are 70/22 and 30/22 respectively by using the first-order condition of differential calculus.

<h3>What is the first-order condition in differential calculus?</h3>

A first-order differential equation is represented by the equation \mathbf{ \dfrac{dy}{dx} =f (x,y) }with 2 variables x & y, including its function f(x,y) specified on a xy-plane.

Given that:

\mathbf{f(x,y) =-22x^2+22xy-11y^2+110x-40y-23}

Let us first differentiate the above equation with respect to x, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial x}  = -44x +22y -0+110-0-0=0}

\mathbf{\implies  -44x +22y+110=0}        (multiply by -1)

44x - 22y = 110    ------ (equation 1)

Now, differentiating with respect to y, we have:

\mathbf{\dfrac{\partial f(x,y) }{\partial y}  =0 +22x-22y +0-40-0=0}

\mathbf{\implies 22x-22y -40=0}

22x - 22y = 40      ----- (equation 2)

Now, we have a system of equations:

44x - 22y = 110

-                      ---- ( subtracting equation 2 from 1; elimination method)

<u> 22x - 22y = 40  </u>

<u>22x    + 0  = 70    </u>

<u />

x = 70/22

Replacing the value of x into equation (1), we have:

44x - 22y = 110

44(70/22) - 22y = 110

140 - 22y = 110

140 - 110 = 22y

30 = 22y

y = 30/22

Learn more about the first-order conditions in differential calculus here;

brainly.com/question/14528981

#SPJ1

4 0
1 year ago
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